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What is the range of numbers that can be encoded in 4 bits using 2s complement notation?
Using 4 bits the signed range of numbers is -8 to 7. When working with signed numbers one bit is the sign bit, thus with 4 bits this leaves 3 bits for the value. With 3 bits there are 8 possible values, which when using 2s complement have ranges: for non-negative numbers these are 0 to 7; for negative numbers these are -1 to -8. Thus the range for signed 4 bit numbers is -8 to 7.
In how many dimensions can form be represented?
3
How many binary bits are needed to represent decimal number 231?
At least 8 bits are needed to represent the number 231. 231 ÷ 2 = 115 r 1 115 ÷ 2 = 57 r 1 57 ÷ 2 = 28 r 1 28 ÷ 2 = 14 r 0 14 ÷ 2 = 7 r 0 7 ÷ 2 = 3 r 1 3 ÷ 2 = 1 r 1 1 ÷ 2 = 0 r 1 → 231 is 1110 0111 in binary and has 8 binary digits. Thus 231 can be represented in 8 bits, but if more are provided, eg 16, it can still be represented (in 16 bits it would be 0000 0000 1110 0111, unless there is a binary point, with say 8 bits after it, then 231 would be 1110 0111 . 0000 0000).
How many 3 digit ascending numbers?
There are 84 such numbers.
Why 1 byte equals to 8 bits?
Because 1 byte is defined [now] to be 8 bits.Digital computers use binary memory locations, ie each memory location can hold one of two values: 0 or 1, as each state is easily representable by whether an electrical charge/voltage exists or not.However, using a BInary digiT, or bit for short, to represent data is not very useful as there are only the two possible data items: 0 and 1. However, by combining more binary digits together into a single unit, more data can be represented in each unit:Using 1 bit only 2 numbers can be represented: 0 & 1Using 2 bits, 4 numbers can be represented: 0, 1, 2 & 3Using 3 bits, 8 numbers can be represented: 0, 1, 2, 3, 4, 5, 6 & 7Using 4 bits, 16 numbers can be represented: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 & 15And so on, every additional bit doubling the quantity of numbers that can be represented.Using 8-bit storage units, two decimal digits can be stored (quite efficiently); this is Binary Coded Decimal (BCD). 8-bit computers became popular (with the manufacturers) probably due to BCD storing two decimal digits in a single unit. I don't know the entymology fully, but I guess that back in the 1950s they needed a term to describe this 8-bit storage unit and either considered it an extended bit (bitE) or as there were eight bits, bit-eight abbreviated to bite. However, it would be very easy to mis- read or write this, so it was deliberately misspelled with a 'y' instead of the 'i': byte.Early microprocessor digital computers used 4 bit units, so that in one storage unit one of 16 different numbers could be stored: 0-9 (the decimal numbers ) and a further 6 numbers (10-15, often represented by the hexadecimal "digits" A-F).When wanting a word to describe the 4-bit storage, the term nybble (nibble spelt with a 'y' - to match bite with a 'y') was probably coined as a pun on taking 2 nibbles of something (eg a piece of cake) and getting a bite out of it.
How many different numbers can be represented by 3 bits?
1000
What is the range of numbers that can be encoded in 4 bits using 2s complement notation?
Using 4 bits the signed range of numbers is -8 to 7. When working with signed numbers one bit is the sign bit, thus with 4 bits this leaves 3 bits for the value. With 3 bits there are 8 possible values, which when using 2s complement have ranges: for non-negative numbers these are 0 to 7; for negative numbers these are -1 to -8. Thus the range for signed 4 bit numbers is -8 to 7.
How many bits in 3 bytes?
1 byte=8 bits SO, 3byts=24 bits
How many bits are required to supernet seven class c address?
3 bits
How many bits can you borrow from 192.168.1.0?
It is possible to borrow a possible 3 bits from 192.168.1.0.
In how many dimensions can form be represented?
3
How many three are in 1 to 9?
This is a very ambiguous question. If you mean how many of the whole numbers from 1 to 9 are multiples of 3, the answer is 3: 3, 6, and 9. But if you want to know the total number of factors of 3 represented by those numbers, the answer is 4, because 9 has 2 factors of 3. There are other possible meanings to the question but I think I have made my point.
How many bits represent the days of the week?
To represent the days of the week, you would need at least 3 bits. With 3 bits, you can represent up to 8 different values (2^3 = 8), which is sufficient to cover all 7 days of the week (Monday to Sunday). Each additional bit would double the number of possible values, but 3 bits are the minimum required to uniquely represent all 7 days.
What is the largest decimal value that can be represented in binary using two bytes?
11b which is 1*2 + 1*1 = 3 would be for two bits. But a byte is 8 bits, so 2 bytes is 16 bits. The largest binary number is [2^16 - 1], which is 65535 (base ten)
What is the quantity that could be represented by the number 2x10- 3?
The quantity that is represented in this number is 17. To come up with the figure, you multiple the two numbers and then subtract the last number.
How many host bits are borrowed if four subnets are created?
3
Explain the bitwise operators available in Java with an example?
Java's bitwise operators operate on individual bits of integer (int and long) values. If an operand is shorter than an int, it is promoted to int before doing the operations. It helps to know how integers are represented in binary. For example the decimal number 3 is represented as 11 in binary and the decimal number 5 is represented as 101 in binary. Negative integers are store in two's complement form. For example, -4 is 1111 1111 1111 1111 1111 1111 1111 1100. == == & - and| - or^ - Xor~ - not> - right shift>>> - right shiftExamples:3 & 5 = 1 (1 if both bits are 1.)3 | 5 = 7 (1 if either bits are 1) 3^5 = 6 (1 if both bits are different)~3 = -4 (Inverts the bits)3 > 2 = 1 (Shifts the bits of n right p positions. If n is a 2's complement signed number, the sign bit is shifted into the high-order positions.)-4 >>> 28 = 15 (Shifts the bits of n right p positions. Zeros are shifted into the high-order positions.){| !!!!!||}
