4
4
no
mike feehan
n1 has 1 n2 has 4
No, the 3f orbital does not exist in the electron configuration of any atom. The f orbitals start appearing at the fourth energy level (n=4) and do not exist at the 3rd energy level.
The lowest energy shell that contains f orbitals is the fourth shell (n=4). Within this shell, the f orbitals are found in the subshell with l=3.
There are 4 orbitals in H2O , one s and 3 p
The lowest value of 'n' that allows a 'g' orbital to exist is 4. 'g' orbitals are part of the f sublevel, which corresponds to the fourth energy level (n=4).
for the case of n=4 the available orbitals include 1s 3p and 5d, a total of 9 electron orbitals which can occupy 18 electrons. There are 18 elements in the 4th row which coincides with the 9 available orbitals.
If it is in row 4 (4th period) it has 4 energy levels occupies. In the 2nd column (group 2A) it has 2 valence electrons. You ask how many orbitals it has. It has s and p orbitals. Is that what you mean? The configuration is 1s2 2s2 2p6 3s2 3p6 4s2 so there are 3 s orbitals and 6 p orbitals for a total of 9 orbitals.
The electrons in beryllium occupy a total of four orbitals. Beryllium has 4 electrons, which fill the 1s, 2s, and 2p orbitals.