Well, there is 16, 64, 144,
above is answered by the first person...
In this problem, the squared number must be a whole number and divisible by 4. 20^2 is 400. And there are 4, 8, 12, 16 ,20; 5 number divisible by 4. and 23^2 is already 529. the next number divisible by 4 is 24 which is over 500. So there are 5 numbers. They are 16, 64, 144, 256, 400.
683 perfect squares.
There are 8 perfect squares TTThe
sqrt(2000) = 44.7sqrt(20000) = 141.4So the perfect squares between 2000 and 20000 are the squares of 45 to 141 (inclusive)ie there are 97 perfect squares in the interval.
68 of them.
500
5 of them.
There is no pair of perfect squares that sums to 21. And the question is pointless if it is not about perfect squares because in that case there are infinitely many answers.There is no pair of perfect squares that sums to 21. And the question is pointless if it is not about perfect squares because in that case there are infinitely many answers.There is no pair of perfect squares that sums to 21. And the question is pointless if it is not about perfect squares because in that case there are infinitely many answers.There is no pair of perfect squares that sums to 21. And the question is pointless if it is not about perfect squares because in that case there are infinitely many answers.
683 perfect squares.
10 perfect squares
There are 8 perfect squares TTThe
There are no four-digit perfect squares that are palindromes.
Two. 36, and 49 are perfect squares.
sqrt(2000) = 44.7sqrt(20000) = 141.4So the perfect squares between 2000 and 20000 are the squares of 45 to 141 (inclusive)ie there are 97 perfect squares in the interval.
No. There are infinitely many perfect squares so there is no "the" perfect square.
there is an infinite number
900
Eight of them.