Oh, dude, it's like super simple. So, to find the remainder of 63 divided by any number, you just divide 63 by that number, and whatever is left over is your remainder. For example, if you divide 63 by 7, you get 9 with no remainder because 7 goes into 63 evenly. But if you divide 63 by 8, you get 7 with a remainder of 7. Easy peasy!
62
62. One less than the divisor.
Then divide the remainder again by the divisor until you get a remainder smaller than your divisor or an remainder equal to zero. The remainder in a division question should never be larger than the "divisor", but the remainder often is larger than the "answer" (quotient). For example, if 435 is divided by 63, the quotient is 22 and the remainder is 57.
The remainder can be greater than the divisor when the dividend is significantly larger than the divisor. In division, the remainder is the amount that is left over after dividing the dividend by the divisor. If the dividend is much larger than the divisor, it is likely that the remainder will also be larger than the divisor.
No, the remainder in a division problem cannot equal the divisor. The remainder is defined as the amount left over after division when the dividend is not evenly divisible by the divisor. By definition, the remainder must be less than the divisor; if it were equal to the divisor, it would indicate that the dividend is divisible by the divisor, resulting in a remainder of zero.
The greatest integer remainder for a division sum with a divisor of 63 would be 62 - for a number one fewer than an integer multiple of 63 - for example, 125/63 = 1 remainder 62.
62
62. One less than the divisor.
Then divide the remainder again by the divisor until you get a remainder smaller than your divisor or an remainder equal to zero. The remainder in a division question should never be larger than the "divisor", but the remainder often is larger than the "answer" (quotient). For example, if 435 is divided by 63, the quotient is 22 and the remainder is 57.
Why not use the Euclidean Algorithm and find out? Divide 63 by 25, and you get a remainder of 13. (The quotient is not important.) Now the divisor of the last division problem becomes the dividend, and the remainder becomes the divisor - that is, we divide 25 by 13 this time. We get a remainder of 12. Divide 13 by 12, and you get a remainder of 1. Divide 12 by 1, you get no remainder. Therefore, this last divisor, 1, is the greatest common factor (or divisor) of the original two numbers. (As a side note, because the gcf is 1, that means those two numbers are what's called relatively prime.)
The divisor is 9. quotient x divisor + remainder = dividend ⇒ quotient x divisor = dividend - remainder ⇒ divisor = (dividend - remainder) ÷ quotient = (53 - 8) ÷ 5 = 45 ÷ 5 = 9
The remainder can be greater than the divisor when the dividend is significantly larger than the divisor. In division, the remainder is the amount that is left over after dividing the dividend by the divisor. If the dividend is much larger than the divisor, it is likely that the remainder will also be larger than the divisor.
No, the remainder in a division problem cannot equal the divisor. The remainder is defined as the amount left over after division when the dividend is not evenly divisible by the divisor. By definition, the remainder must be less than the divisor; if it were equal to the divisor, it would indicate that the dividend is divisible by the divisor, resulting in a remainder of zero.
quotent X divisor + remainder = dividend
What is the largest remainder possible if the divisor is 10
Because if the remainder is greater, then you could "fit" another divisor value into it. if they are equal, then you can divide it easily. Thus, the remainder is always lower than the divisor.
If the remained was bigger than the divisor than the divisor could still be taken out of the remainder