0
To determine the remainder, you would take 63 and see how many times your divisor fits into it. That will give you a number, which when multiplied by the divisor will be less than 63, and smaller than the divisor. Subtract the result of your divisors times your quotient from 63, and that number is the remainder.
Add your answer:
Earn +20 pts
What is the greatest remainder possible if the divisor is 63?
62
What is the largest remainder possible if the divisor is 63?
62. One less than the divisor.
What if your remainder is bigger than your answer?
Then divide the remainder again by the divisor until you get a remainder smaller than your divisor or an remainder equal to zero. The remainder in a division question should never be larger than the "divisor", but the remainder often is larger than the "answer" (quotient). For example, if 435 is divided by 63, the quotient is 22 and the remainder is 57.
Why does the remainder be greater then the divvisor?
The remainder can be greater than the divisor when the dividend is significantly larger than the divisor. In division, the remainder is the amount that is left over after dividing the dividend by the divisor. If the dividend is much larger than the divisor, it is likely that the remainder will also be larger than the divisor.
What is the largest remainder possible if the divisor is 10?
What is the largest remainder possible if the divisor is 10
What is the greatest possible remainder if the divisor is 63?
The greatest integer remainder for a division sum with a divisor of 63 would be 62 - for a number one fewer than an integer multiple of 63 - for example, 125/63 = 1 remainder 62.
What is the greatest remainder possible if the divisor is 63?
62
What is the largest remainder possible if the divisor is 63?
62. One less than the divisor.
What if your remainder is bigger than your answer?
Then divide the remainder again by the divisor until you get a remainder smaller than your divisor or an remainder equal to zero. The remainder in a division question should never be larger than the "divisor", but the remainder often is larger than the "answer" (quotient). For example, if 435 is divided by 63, the quotient is 22 and the remainder is 57.
What is the greatest common factor of 25 and 63?
Why not use the Euclidean Algorithm and find out? Divide 63 by 25, and you get a remainder of 13. (The quotient is not important.) Now the divisor of the last division problem becomes the dividend, and the remainder becomes the divisor - that is, we divide 25 by 13 this time. We get a remainder of 12. Divide 13 by 12, and you get a remainder of 1. Divide 12 by 1, you get no remainder. Therefore, this last divisor, 1, is the greatest common factor (or divisor) of the original two numbers. (As a side note, because the gcf is 1, that means those two numbers are what's called relatively prime.)
What is the divisor when the dividend is 53 and the quotient is 5 with a remainder of 8?
The divisor is 9. quotient x divisor + remainder = dividend ⇒ quotient x divisor = dividend - remainder ⇒ divisor = (dividend - remainder) ÷ quotient = (53 - 8) ÷ 5 = 45 ÷ 5 = 9
Why does the remainder be greater then the divvisor?
The remainder can be greater than the divisor when the dividend is significantly larger than the divisor. In division, the remainder is the amount that is left over after dividing the dividend by the divisor. If the dividend is much larger than the divisor, it is likely that the remainder will also be larger than the divisor.
Divisor and remainder is given find the dividend?
quotent X divisor + remainder = dividend
What is the largest remainder possible if the divisor is 10?
What is the largest remainder possible if the divisor is 10
Why should the remainder be less than the divisor?
Because if the remainder is greater, then you could "fit" another divisor value into it. if they are equal, then you can divide it easily. Thus, the remainder is always lower than the divisor.
What is the hcf of 60 and 63?
The highest common factor (HCF) of 60 and 63 is 3. To find the HCF, you can use the Euclidean algorithm, which involves dividing the larger number by the smaller number and then using the remainder as the new divisor in the next iteration. This process continues until the remainder is zero, at which point the last non-zero divisor is the HCF. In this case, 63 divided by 60 is 1 with a remainder of 3, so the HCF is 3.
Why must the remainder be smaller than the divisor?
If the remained was bigger than the divisor than the divisor could still be taken out of the remainder
