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How many pounds of candies that sells for 75 per lb must be mixed with candy that sells for 1.25 per lb to obtain 9 ib of mixture that should sell for 96 per lb?
Wiki User
∙ 11y ago
Let x = pounds of $0.75 candy, and let y = pounds of $1.25 candy.
From the question, we know the total pounds must equal 9, and the total price should be 9 pounds at $0.96 per pound. Thus the total price should be 9*0.96 = $8.64.
We can form two equations; one for total pounds, and one for total price:
x+y = 9
0.75x+1.25y = 8.64
Solve for x in the first equation: x = 9-y
Plug that into the second equation for x: 0.75(9-y) +1.25y = 8.64
Simplify: 6.75 - 0.75y + 1.25y = 8.64
More: 6.75 + 0.5y = 8.64
More: 0.5y = 1.89
Divide both sides by 0.5: y = 3.78
Plug that into the first equation: x + 3.78 = 9
Solve for x: x = 5.22
Thus, we need 5.22 pounds of $0.75 candy and 3.78 pounds of $1.25 candy
Wiki User
∙ 11y ago
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