Q: How many prime factors of 48 are there?

Write your answer...

Submit

Still have questions?

Continue Learning about Other Math

48 = 24 x 3

48 = 24 x 3

TO work out the HCF you need to split the numbers into their prime factors. In this case you have: 40 = 2x2x2x5 48 = 2x2x2x2x3 The next step is to identify any common prime factors. Both numbers have three 2s as prime factors. Multiply these together and you get: 2x2x2 = 8 Thus the HCF of 40 and 48 is 8.

To find the HCF of these two numbers, you have to break them down into their prime factors: 48 = 2x2x2x2x3 76 = 2x2x19 The next step is to identify any common prime factors. In this case both numbers have two 2s as prime factors. Multiply these together and you get 4. Therefore 4 is the HCF of 48 and 76.

10 factors

Related questions

The prime factors are: 2,3

The prime factors of 48 are: 2, 3

48 has only 2 prime factors, not 8!

The prime factors are: 2, 3

no 48 is not a prime number. A prime number is a number that only have 1 and itself as factors.

No because prime factors are: 22223 = 48

They are 2 and 3

The answer is three (3).48 = 2x3x2x2x2 (prime factors)72 = 3x3x2x2x2 (prime factors)

1x2x2x2x2x3=48

2 and 3 are factors of 48 and prime numbers.

48 has only two prime factors: 2 and 3.

Factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48; of these the only primes are 2 and 3, all other factors of 48 not being prime.