There are 2 prime factors of 48. The prime factorization of 48 is:
24 x 3 = 48
48 = 24 x 3
48 = 24 x 3
10 factors
TO work out the HCF you need to split the numbers into their prime factors. In this case you have: 40 = 2x2x2x5 48 = 2x2x2x2x3 The next step is to identify any common prime factors. Both numbers have three 2s as prime factors. Multiply these together and you get: 2x2x2 = 8 Thus the HCF of 40 and 48 is 8.
To find the HCF of these two numbers, you have to break them down into their prime factors: 48 = 2x2x2x2x3 76 = 2x2x19 The next step is to identify any common prime factors. In this case both numbers have two 2s as prime factors. Multiply these together and you get 4. Therefore 4 is the HCF of 48 and 76.
The prime factors are: 2,3
The prime factors of 48 are: 2, 3
The prime factors of 48 are: 1, 2, 24, & 48 1 x 48 & 2 x 24
The prime factors are: 2, 3
The factors of -48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 48 and their negatives. The prime factors are 2 and 3
The factors of 48 are: 1 2 3 4 6 8 12 16 24 48. The prime factors are: 2 3
They are 2 and 3
No because prime factors are: 22223 = 48
no 48 is not a prime number. A prime number is a number that only have 1 and itself as factors.
Its prime factors are 2 and 3As a product of its prime factors: 2*2*2*2*3 = 48
1x2x2x2x2x3=48
The answer is three (3).48 = 2x3x2x2x2 (prime factors)72 = 3x3x2x2x2 (prime factors)