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Q: How many prime factors of 48 are there?

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48 = 24 x 3

48 = 24 x 3

10 factors

TO work out the HCF you need to split the numbers into their prime factors. In this case you have: 40 = 2x2x2x5 48 = 2x2x2x2x3 The next step is to identify any common prime factors. Both numbers have three 2s as prime factors. Multiply these together and you get: 2x2x2 = 8 Thus the HCF of 40 and 48 is 8.

To find the HCF of these two numbers, you have to break them down into their prime factors: 48 = 2x2x2x2x3 76 = 2x2x19 The next step is to identify any common prime factors. In this case both numbers have two 2s as prime factors. Multiply these together and you get 4. Therefore 4 is the HCF of 48 and 76.

Related questions

The prime factors are: 2,3

The prime factors of 48 are: 2, 3

The prime factors of 48 are: 1, 2, 24, & 48 1 x 48 & 2 x 24

The prime factors are: 2, 3

The factors of -48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 48 and their negatives. The prime factors are 2 and 3

The factors of 48 are: 1 2 3 4 6 8 12 16 24 48. The prime factors are: 2 3

They are 2 and 3

No because prime factors are: 22223 = 48

no 48 is not a prime number. A prime number is a number that only have 1 and itself as factors.

Its prime factors are 2 and 3As a product of its prime factors: 2*2*2*2*3 = 48

1x2x2x2x2x3=48

The answer is three (3).48 = 2x3x2x2x2 (prime factors)72 = 3x3x2x2x2 (prime factors)

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