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You need to know how high the water column is to calculate the pressure it exerts at its base! For example, a column of water 1 metre deep would exert a pressure of 9.81 kPa at its base (density x gravity x depth - 1000 * 9.81 * 1). This would be equal to approx 1.42 PSI.
613 Torr = 81.726386 kPa
108 ÷ 63 = 1 with remainder 45
36 inches = 1 yard so 108 inches = 108/36 = 3 yards. Simple.
108