You can get 63 questions wrong and get 70%.
If you make the assumption - without any justification - that all questions are worth the same, then each one is worth 1/35 of the total for the exam.
That depends on what is passing grade? Is it 60%? Then 0.80 (.55) + .20 (x) = .60 .44 + .20X = .6 .20X = .16 x = .80 That means you need to get 8 of every 10 questions right to get 60 percent average.
330 ways. Once we know he must answer the last question, the issue is really one of choosing 4 questions from the first 11 questions on the exam. There are 11 ways to choose the first question, 10 ways to choose the second, 9 ways to choose the third, and 8 ways to choose the fourth, so that would be 11*10*9*8... but the order of the questions doesn't matter. So we divide by the number of ways to rearrange the 4 questions (4*3*2*1=24), to get 330.
points is each question worth on a 12 question exam?
80% is simply 8/10 or .8. So multiply 35 by .2 and you get your answer, 7. To get an 80% on a 35 question exam you will have answered 28 questions correct and 7 incorrect. Percentages tend to confuse people but they don't have to. If you think of 100% as nothing more than 1 than you are well on your way to mastering %'s and fractions too. Let's look at your original question. You want to know how many questions you can miss out of 35 and still receive an 80%. First thing to do is convert 80% to decimal form and you do that by simply moving the decimal 2 places to the left from where it currently is. Where is it you may ask? It is implied that if it is not shown then it is directly following the last number. So 80% would mean the decimal is directly following the zero or to show it written it would look like this 80.%. Okay move it two positions to the left and you drop the percent symbol to come up with a simple decimal form of this .80 or just .8. The first number to the right of the decimal is the tenths position right? Right! So as a fraction it is written as 8/10. Now your question asked how many you could get wrong. If you multiply 35 by .8 you will come up with how many you must get right. So to figure how many you may get wrong take 1 and subtract .8. Your answer is .2 and now simply multiply 35 by .2 to get the number you may get wrong and still receive an 80% on the exam.
Provided that all 150 exam questions are weighted equally, then 105 correct responses is 70%.
All of them - if you are bad enough. You will not pass, but that was not a requirement of the question.
To ensure you understand what the question is. It is possible to misunderstand the question and therefor provide the wrong answer.
40 minus 28 = 12 were wrong
Dmitri Mendeleev's demerit is the common question in all the exam's,
Where can I find the questions to the Ca. Life and Health exam?
stop asking such wrong questions here or anywhere for that matter. Study hard
Can you please provide more specific information or context about the deck cadet exam question?
You would have too ask the person who set the exam. However - they don't HAVE to tell you.
not studying or revising nerves not reading the question properly so you give the wrong answer not understanding the subject turning up for the exam on the wrong day or time!
"where someone accidentally sits the wrong exam" ??? Um... what? Perhaps you should rephrase this and perhaps someone can answer your question.
75%