0
4, assuming the final 0 is there for a good reason.
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∙ 11y ago
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∙ 7y ago4 of them.
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How many significant digits are in 0.0250 cm3?
Three
How many cm3 in 1m3?
10 000 cm3
How many cm3 is 1dm3?
1 dm3 = 1000 cm3 :)
Examples in multiplication and division of significant figures?
Multiplication and DivisionRound the answer to the same number of significant figures (sig figs) as the measurement with the fewest sig figs in the problem.34.9cm x 4.7cm = 164.03cm2 = 160cm2 (rounded to two sig figs)271.0g/99.8cm3 = 2.71543g/cm3 = 2.715 (rounded to four sig figs)Addition and SubtractionRound the answer to the fewest decimal places as the measurement with the fewest decimal places.9.45kg + 8.329kg = 17.78kg (rounded to two decimal places)
How many cm cubes are there in 1000 liters?
1 litre = 1,000 cm3 2 litres = 2,000 cm3 10 litres = 10,000 cm3 100 litres = 100,000 cm3 1,000 litres = 1,000,000 cm3
What is the density of a rock that has a mass of 22.4g and a volume of 8cm3?
Density = mass/volume Density = 22.4g/8cm3 = 2.8g/cm3 or 3g/cm3 if significant figures are considered.
How many significant digits are in 0.0250 cm3?
Three
What is the density of a mineral with a mass of 41.2 g and a volume of 8.2 cm3?
Density is found by dividing mass by volume. D=M/V D=41.2g/8.2cm3 D=5.02439g/cm3 With the significant figures being at 2 because of 8.2cm3, the answer is 5.0g/cm3
What is the density of a sample of ore that has a mass of 57g and occupies What is the density of a sample of ore that has a mass of 57 g and occupies 29 cm3 Answer in units of g cm3?
Density = mass/volume, So, Density = 57g/29cm3 = 2.0g/cm3* The number on the calculator is 1.965517241, which is rounded to 2.0 because of significant figures.
What is the density of a mineral with a mass of 41.2 g and a volume of 8.2?
Density is found by dividing mass by volume. D=M/V D=41.2g/8.2cm3 D=5.02439g/cm3 With the significant figures being at 2 because of 8.2cm3, the answer is 5.0g/cm3
The density of ethanol is 0.789 gcm3 at 20 and degC. What volume of ethanol has a mass of 15.5 grams?
Use the formula M=DV mass= density x volume m= 0.7989 g/mL(17.4 mL)
What is the density of a rock which has a mass of 35 grams and a volume of 7.0 cubic centimeters?
To calculate density, you must calculate the mass divided by the volume. Therefore, density=234 g/ 2.9 cm3 = 80.6896... g/cm3 or 81 g/cm3 using significant figures.
What is the volume of an irregularly shaped chunk of copper with a mass of 1.5 kg?
Unknown: Volume of chunk of copperKnown:density = 8.94g/cm3 (Wikipedia)mass of irregularly shaped chunk of copper = 1.5kg = 1500gEquation:density = mass/volumeSolution:volume = mass/density = 1500g/8.94g/cm3 = 167.8cm3 = 170cm3 (rounded to two significant figures)
What is the mass of 136 mL of Mercury?
If you know the density of mercury, you can determine the mass of a specific volume of mercury. Mercury has a density of 13.534g/cm3. 1cm3 = 1mL, so we can restate its density as 13.534g/mL. Density = mass/volume. If we know any two variables, we can manipulate the density equation to find the third variable. In this case, we know volume and density, so to find the mass, do the following calculation: Mass = density x volume Mass Hg = 13.534g/mL x 136mL = 1.84g Hg* *The answer is limited to 3 significant figures, because 136mL has only 3 significant figures, even though the density has 5 significant figures. When multiplying or dividing, the answer is limited to the same number of significant figures as the measurement with the fewest significant figures used in the calculation.
How many liters are in 2540 cm3?
1ml = 1cc 1000 cc in 1 l So, you have 2.54 liters in 2540 cc. Note, the significant figures in an integer are ambiguous, and you could also have 2.540 l
What is the volume of 27 g of aluminum?
If you know the density of aluminum, you can determine the volume of a specific mass of aluminum. Aluminum has a density of 2.70g/cm3. Density = mass/volume. If we know any two variables, we can manipulate the density equation to find the third variable. In this case, we know mass and density, so to find the volume, do the following calculation: Volume = mass/density Volume Al = (27g Al)/(2.70g/cm3 Al) = 10cm3 Al. So, 27g of Al has a volume of 10cm3. * * This answer should technically have two significant figures. As written, it only has one, because trailing zeroes without a decimal are not significant. We can indicate two significant figures by writing it in scientific notation as 1.0 x 101cm3, or we can write it with a decimal as 10. cm3.
What is the mass of a sample of material that has a volume of 77 cm 3 and a density of 7.83 gcm3?
The material has a density of about 0.848 g/cm3
