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Why is the volume reported in two significant figures?

It varies. Volume may be reported with more or less significant figures. However, in general the result should not have more significant figures than the underlying data - otherwise, it would look more accurate than it really is.


Why is volume reported in two significant figures?

The question is based on a fallacy. Volumes can be reported in any number of significant figures.


What is the density of a sample of ore that has a mass of 57g and occupies What is the density of a sample of ore that has a mass of 57 g and occupies 29 cm3 Answer in units of g cm3?

Density = mass/volume, So, Density = 57g/29cm3 = 2.0g/cm3* The number on the calculator is 1.965517241, which is rounded to 2.0 because of significant figures.


Why is density expressed in two significant figures?

Because density expressed in two significant figures depends on your accuracy of your measurements of mass and volume to calculate as well as any variables that you are expected to use.


What is the mass of a sample of material that has a volume of 77 cm 3 and a density of 7.83 gcm3?

The material has a density of about 0.848 g/cm3


A water sample has a volume of exactly 12.0000mL How would this volume be recorded if it were measured from a a 50-mL graduated cylinder?

The volume of 12.0000 mL would be recorded as 12.00 mL when measured from a 50-mL graduated cylinder because the cylinder has markings in increments of 1 mL. It is standard practice to record the volume to two decimal places for greater accuracy.


What is the density of mercury if a 25.0 mL sample has a mass of 338.35 g?

(338.5 g) / (25.0 mL) = 13.5 g/mL (3 significant figures)


Is the unit of a number have importance in significant figures?

No, the units are independent of the accuracy. If you are measuring volume, how accurate the measurement is (or isn't) will not affect what you are measuring - it will always be volume.


What determines the number of significant figures in density calculations?

The accuracy of the measurement device determines the number of significant figures that should be retained in recording measurements.


What is the mass of 136 mL of Mercury?

If you know the density of mercury, you can determine the mass of a specific volume of mercury. Mercury has a density of 13.534g/cm3. 1cm3 = 1mL, so we can restate its density as 13.534g/mL. Density = mass/volume. If we know any two variables, we can manipulate the density equation to find the third variable. In this case, we know volume and density, so to find the mass, do the following calculation: Mass = density x volume Mass Hg = 13.534g/mL x 136mL = 1.84g Hg* *The answer is limited to 3 significant figures, because 136mL has only 3 significant figures, even though the density has 5 significant figures. When multiplying or dividing, the answer is limited to the same number of significant figures as the measurement with the fewest significant figures used in the calculation.


What is the density of a rock that has a mass of 22.4g and a volume of 8cm3?

Density = mass/volume Density = 22.4g/8cm3 = 2.8g/cm3 or 3g/cm3 if significant figures are considered.


What is the volume of a sphere with radius 7.5?

Volume = 4/3 * pi * r3 Volume = 4/3 * pi * (7.5)3 = 1767 ( units ) ----------------------------though the significant figures constraint may show 1800