The question is based on a fallacy. Volumes can be reported in any number of significant figures.
The more significant figures a number has the more accurate it is. In commercials for germicidal sprays, would you buy the product that is 99% effective or 99.99% effective?
Two sf.
Because density expressed in two significant figures depends on your accuracy of your measurements of mass and volume to calculate as well as any variables that you are expected to use.
42 has two significant figures.
Rounded to two significant figures it becomes 1.0e4
Rounded to two significant figures it becomes 3.6
It varies. Volume may be reported with more or less significant figures. However, in general the result should not have more significant figures than the underlying data - otherwise, it would look more accurate than it really is.
Two significant figures the measurment 0.0255 g should be reported as 0.026g
When the value 4,449 is rounded to two significant figures the number should be reported as 4,400
The number 0.0950 has 3 significant figures. Those are the 9, 5, and final 0. The first two zeros on the left, are not significant.
Two sf.
Three, so the answer would be 3.96. Always use the number with the smallest amount of significant figures to determine the amount of significant figures will be in the solution.
Because density expressed in two significant figures depends on your accuracy of your measurements of mass and volume to calculate as well as any variables that you are expected to use.
There are two significant figures which are the two 2s.
There are 4 significant figures in 0.0032. Seems to be only 2 significant figures in this number.
22.1 to two significant figures = 22
23.81558 to two significant figures is 24.
42 has two significant figures.