That's going to depend on what shape you're building,
which, as far as I can see, you neglected to mention.
16 straws and 6 plasticine
16 straws and 6 plasticine
6
6 of them
10
<X X> It should look kinda like the example above. Except it would be squares lol. Make two crosses with the 4 long straws put the ends of these together so that one square is made then make two right angles with the four short straws and place them at the other side of each cross to make three squares in a diagonal line. :)
Quarter to four would be 3:45
6
6
The answer will depend on what the shape is. And since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer.
16 straws.
You would need 12 straws because a cuboid has 12 edges, 8 vertices and 6 faces
9 straws because it has 9 edges, 6 vertices and 5 faces
You would need 12 straws of equal sizes because a cube has 12 equal edges, 8 vertices and 6 faces
18 of them because an hexagonal prism has 18 edges
There are various types of dodecahedrons. A regular dodecahedron has twelve faces, each with five edges. Altogether there are thirty edges. So you could make a regular dodecahedron with thirty straws, or one very long one! You could even make one with sixty straws, but you would have to join them together in pairs to make the thirty edges! For more information, see 'Related links' below this box.
assuming the straws do not bend, you would need six
A crotchet is one quarter of a whole note. A semibreve rest is one whole note. Therefore, a semibreve would have how many quarter notes (crotchet)?
If the straw were normal and 8.25 inches then it would take 4.772121212121212... straws.