0
To find the number of three-digit positive integers with digits whose product is 24, we can break down 24 into its prime factors: 2 x 2 x 2 x 3. The possible combinations for the three digits are (2, 2, 6), (2, 3, 4), and (2, 4, 3). These can be arranged in 3! ways each, giving a total of 3 x 3! = 18 three-digit positive integers.
Add your answer:
Earn +20 pts
How many 3 digit positive integers have 5 as the product of their digits?
Three of them.
What percentage of the first 100 positive integers contains no even digits?
50%
How many positive integers less than 100 have the sum of their digits equal to a perfect square?
There are 20.
What is a bijective numeration?
A bijective numeration is a numeral system which uses digits to establish a bijection between finite strings and the positive integers.
How many positive integers less than 100 can be written using the digits 6 7 8 9?
20. 16 without repeating a digit.
How many 3 digit positive integers have 5 as the product of their digits?
Three of them.
What is the sum of all positive integers less than 100 that have the product of their digits equal to 4?
81
What is the sum of all the digits of all the positive integers that are less than 100?
The sum of all the digits of all the positive integers that are less than 100 is 4,950.
What is the sum of positive six digit integers whose digits are a permutation of the digits in the number 123456?
279,999,720
What percentage of the first 100 positive integers contains no even digits?
50%
What are the last two digits in the sum of factorials of the first 100 positive integers?
They are 13.
How many positive integers less than 1000 have no odd decimal digits?
52
How many positive integers ar equal to 12 times the sum of their digits?
There are none.
How many positive integers have exactly three digits?
Every number from 100 to 999 inclusive !
How many positive integers have equally many digits in the decimal representation of their square and their cube?
3
Find the sum of the digits in the smallest positive integers that is divisible by 2 and 4 and 6 and 10 and 12 and 14?
The sum of the digits is 6.
A 2 digit number that is the product of 2 consecutive integers and the sum of its digits is greater than the product of the digits both digits are even?
The 2-digit number must be 20, because it is the only 2-digit number whose sum of its two even digits, 2 + 0 = 2, is greater than the product of its two even digits, 2 x 0 = 0. Moreover, 20 is a product of the two consecutive integers 4 and 5.
