To find the number of three-digit positive integers with digits whose product is 24, we can break down 24 into its prime factors: 2 x 2 x 2 x 3. The possible combinations for the three digits are (2, 2, 6), (2, 3, 4), and (2, 4, 3). These can be arranged in 3! ways each, giving a total of 3 x 3! = 18 three-digit positive integers.
Three of them.
50%
There are 20.
A bijective numeration is a numeral system which uses digits to establish a bijection between finite strings and the positive integers.
20. 16 without repeating a digit.
Three of them.
81
The sum of all the digits of all the positive integers that are less than 100 is 4,950.
279,999,720
50%
52
There are none.
They are 13.
To find the number of 7-digit positive integers where the product of the digits equals 10,000, we start by factoring 10,000 into its prime factors: (10,000 = 10^4 = (2 \cdot 5)^4 = 2^4 \cdot 5^4). The digits can only be from 1 to 9, so we can use digits like 1, 2, 4, 5, 8, etc., that can contribute to this product. Combinations of these digits that yield a product of 10,000 must be examined, but the key constraint is that the total number of digits must equal 7. This requires a systematic approach to explore all valid combinations of digits that meet these criteria, which can be complex and requires further analysis involving combinatorial counting and digital constraints. The exact count of such integers is not straightforward without deeper calculations and could vary significantly based on the digit choices made.
3
Every number from 100 to 999 inclusive !
The sum of the digits is 6.