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8. A way to work this out is figure out how many possible digits can go in each place value position (units, tens, hundreds) and multiply these together. Since there are 2 possible digits that can go in each position and there are three positions, you would go: 2 x 2 x 2 = 8 Want a list? 222 225 252 255 555 552 525 522
27 and 81; 27 + 81 = 108, and 3 x 27 = 81
There is no set of three consecutive integers for 187.
That isn't possible; three consecutive integers, or three consecutive positive integers, always have a sum that is a multiple of 3. In general, you can solve this quickly by trial and error. In this case, you will quickly find that a certain set of three consecutive integers will give you a sum that is TOO LOW, while the next-higher even integers will give you a sum that is TOO HIGH. You can also write an equation and solve it: n + (n + 2) + (n + 4) = 32. If you solve it, you will find that the solution is fractional, not integral.
9240 is the product of the three consecutive integers 20, 21, and 22.