Best Answer

The first digit can be any one of 5 choices. For each of those, the second digit can be any one of 4 choices. For each of those, the third digit can be any one of 3 choices. So the total number of permutations without repetition is 5 x 4 x 3 = 60.

Q: How many three digit numbers can you write using the digits 1 2 3 4 5 without repeating?

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-58264

Forming three three digit numbers that use the numbers 1-9 without repeating, the highest product possible is 611,721,516. This is formed from the numbers 941, 852, and 763.

9876543210

9,876,543,210 9876543210

There are 25 such numbers.

Related questions

24

256

18, if leading 0s are disallowed.

Without repeating digits (not digets!) and without leading 0s, 600 of them.

98765

60

-58264

86420

It is a repeating decimal.

468, 486, 648, 684, 846, 864.

4 x 3 x 2 ie 24

5040