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Clearly A, B, and C are digits between zero and eight. A takes any value from 1 to 8.* There are thus eight possibilities for the value of A. Each value of A will dictate a value N, from 0 to 7, for (B+C). For a given value of N, B can take any value from 0 to N, and thus can take N + 1 different values, each corresponding to a particular value of C. So there are N + 1 ways of achieving (B+C) = N. The total number of combinations is therefore add up [N+1] between N=0 and N=7 = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 = (8 + 1) x 8/2 = 9 x 4 = 36 And here are those 36 solutions: 800,701,710,611,620,602,521,512,530,503,422,431,413,440,404,332,323,341,314,350,305,233,242,224,215,251,206,260,143,134,152,125,116,161,107,170 *If A was zero, we wouldn't really have a three digit number as required.
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How many different numbers can be formed with the digits 345?
Assuming you mean permutations of three digits, then the set of numbers that can be made with these digits is: 345 354 435 453 534 543 There are six possible permutations of three numbers.
How many digits are are used for printing the page numbers of a book that has 115 pages?
Three digits.
How many significant digits are there in the number 938?
All three numbers are significant digits, so 3.
How many three digit numbers is average of three digits equal to 2?
21
How many whole numbers have exactly three digits how did you find that out and tell me why that's the answer?
Assuming that 001, 080, etc are not allowed (that is a leading zero or two is not permitted), the smallest number with exactly three digits is 100. The largest number with exactly three digits is 999. So there are 999 - 100 + 1 = 900 numbers with exactly three digits.
