If the digits are all different then 18. Otherwise, 192.
There are 60480 numbers.
1 set
There are 4^6 = 4096 such numbers.
6*5*4*3*2*1=720
There are 7,290 different 4-digit numbers that can be formed from the digits 1-9 without repetition.
If the digits are all different then 18. Otherwise, 192.
Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits. There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundred’s place respectively. So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120 Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360. the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720. The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720. So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.
To form a 3-digit number less than 500 with different digits from 3, 4, 5, and 9, we need to consider the following cases: For the hundreds place: 3, 4, and 5 are available options. For the tens place: Any of the remaining three digits can be used. For the units place: Any of the two remaining digits can be used. Therefore, the total number of 3-digit numbers that can be formed is 3 (choices for hundreds place) x 3 (choices for tens place) x 2 (choices for units place) = 18 numbers.
10,000
36
100000 - including numbers with leading 0s
99999
192, including ones containing repeat digits.
how make the answer im don/now
6 if you don't repeat any.
There are 5*4*3 = 60 such numbers.