-475
Once! After you have subtracted it once, you are subtracting 100 from 1900, and then 100 from 1800 and on and on
-10
20 times
3x - 20 = 46 3x = 46 + 20 3x = 66 x = 66/3 x = 22 Therefore, the number is 22! :)
34 can go into 54 once, with a remainder of 20. This is because 34 is the largest multiple of 34 that is less than 54, which is 34 itself. When 34 is subtracted from 54, the remainder is 20.
495 ÷ 25 = 19 with remainder 20.
-20
(4x-20) = 119
20% of 495= 20% * 495= 0.2 * 495= 99
2.3 subtracted from 20 = -17.7
3.47 subtracted from 20 = -16.53
24.75
2013 subtracted from1993 = 20
a number times 3 subtracted by 20 is -4 a x 3 - 20= -4
You can subtract 5 from 100 a total of 20 times before you reach zero. Each subtraction decreases the total by 5, so after 20 subtractions, you would have 0 left. However, if you consider the question literally, you can subtract 5 from 100 as many times as you want, but the meaningful answer is that you can do it 20 times until you no longer have a positive number.
141+20=161, 161/7=23. The answer is 23. It is algebra
15 and 20 respectively. added, they are 35 mins. Subtracted, the answer is 5 mins