20
6 times
The lowest three digit odd number would have to be -999.However, if you mean the lowest three digit positive number, it would be 101.
-998 would have to be the lowest three digit even number. If you mean a positive number, it would be 100.
16 times 25 is equal to 400. This can be calculated by multiplying 16 by 25 using the standard multiplication method. To do this, you would multiply the units digit of the first number by the units digit of the second number (6 x 5 = 30), carry over the 3, then multiply the tens digit of the first number by the units digit of the second number and add the carried over 3 (2 x 5 + 3 = 13), which gives you the final answer of 400.
93 and 7 would be an example.
Oh, what a lovely question! Let's take a moment to appreciate the beauty of numbers. In a book with 382 pages, the number of times the digit 3 is used to number the pages would depend on how the pages are numbered. If we're counting individual pages (1, 2, 3...), you would find the digit 3 used 60 times. If we're counting in sets of 10s (10, 20, 30...), you would find the digit 3 used 40 times. Just like painting, it's all about perspective and how you choose to look at things.
6 times
4
2
You would need 20 twos to number the pages from 1 to 232. This is because there are 20 occurrences of the digit two in the numbers from 1 to 232.
A decimal number is simply a way of representing a number in such a way that the place value of each digit is ten times that of the digit to its right. It would appear that that is the case for this number.
If you allow non integers, then your smallest four-digit number would be .0001. If you only allow integers, then your smallest four-digit number would be 1000. Your largest four-digit number would be 9999.
There are 9 pages that use a single digit (pages 1-9), leaving 495 digits - 9 pages × 1 digit/page = 486 digits There are 90 pages that use 2 digits (pages 10-99), leaving 486 digits - 90 pages × 2 digits/page = 306 digits There are 900 pages that use 3 digits (pages 100-999); this would be 2,700 digits, so the number of pages is somewhere in the hundreds. 306 digits ÷ 3 digits/page = 102 pages in the hundreds. → total number of pages = 102 + 90 + 9 = 201 pages.
To form a three-digit number using the digits 0-9, the first digit cannot be 0 (as it would not be a three-digit number). Thus, the first digit can be any of the digits from 1 to 9 (9 options). The second and third digits can each be any digit from 0 to 9 (10 options each). Therefore, the total number of three-digit numbers is (9 \times 10 \times 10 = 900).
9
This is impossible to answer ! According to your rules - starting from the right-ham digit... Say the right-hand digit is 1 - the value of the figure to the left of that would be 7, the next value would be 28, and the fourth would be 196 !
The lowest three digit odd number would have to be -999.However, if you mean the lowest three digit positive number, it would be 101.