The number of triangles formed by the diagonals of a 21 sided polygon is C(21,3) = 21x20x19/3x2x1 = 1,330.
98
18 triangles
There are 90 diagonals in a 15-sided polygon.
A 4-sided polygon has 2 diagonals. A 5-sided polygon, 5. 6-sided, 9. By induction, an n-sided polygon has 'n*(n-3)/2' diagonals. "n" is how many sides a shape has. so, (7)*(7-3)/2 now we have, 7*4/2 so, 28/2 = 14 Therefore, a 7-sided polygon would have 14 diagonals.
The number of triangles that can be formed within a regular polygon depends on the number of sides the polygon has. For an n-sided polygon, where n is greater than or equal to 3, you can form n-2 triangles within the polygon. This is because each triangle is formed by connecting one vertex to any other two non-adjacent vertices. So, for example, in a regular pentagon (5-sided polygon), you can form 5-2 = 3 triangles.
Two triangles can be formed by the diagonals of one vertex of a four-sided polygon.
98
98
In a 100-sided polygon, if diagonals are drawn from one vertex, they connect to all non-adjacent vertices. A vertex connects to 97 other vertices (100 total vertices minus the 1 vertex itself and the 2 adjacent vertices). The number of triangles formed with the diagonals from that vertex is given by the formula for combinations, specifically ( \binom{97}{2} ), which equals 4,656 triangles.
18 triangles
There is no such polygon that has 95 diagonals because a 15 sided polygon has 90 diagonals and a 16 sided polygon has 104 diagonals.
An 11 sided polygon has 44 diagonals.
There are 90 diagonals in a 15-sided polygon.
A four-sided polygon has two diagonals.
Well, honey, let me break it down for you. In a 13-sided polygon, you can form 11 triangles by connecting the vertices. Each triangle is formed by choosing 3 vertices out of 13, which can be done in 13 choose 3 ways, resulting in 286 total triangles. So, there you have it - 286 triangles in a 13-sided polygon.
To determine how many triangles can fit into a 13-sided polygon, we can use the formula for the number of triangles that can be formed from the vertices of an n-sided polygon, which is given by ( \binom{n}{3} ). For a 13-sided polygon, this is ( \binom{13}{3} = \frac{13 \times 12 \times 11}{3 \times 2 \times 1} = 286 ). Therefore, 286 triangles can be formed using the vertices of a 13-sided polygon.
13 triangles will be formed