To determine the number of triangles that can be formed with side lengths of 4m, 4m, and 7m, we can use the triangle inequality theorem. For a triangle to exist, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4m + 4m = 8m, which is greater than 7m. Therefore, a triangle can be formed. Since all three sides are equal in length, this triangle is an equilateral triangle. So, there is only one triangle that can be formed with side lengths of 4m, 4m, and 7m.
As many as you like but they will all be scalene triangles formed by the given angles that add up to 180 degrees
There is only one equilateral triangle with a perimeter of 60 units. Its side lengths are integers.
It depends on the question you are asked. There are never 3 distinct triangles; there can only be 0,1, or 2 distinct triangles. Idk if that helps because the question is kinda general.
There is only one triangle. Or two if you count its mirror image as a different triangle.
Yes, any length - from virtually zero to that of the diameter.
How many triangles exist with the given side lengths 3in, 4in, 2in
There is only one.
More than one unique triangle exist
Exactly one unique triangle exists with the given side lengths.thank u...
It is an isosceles triangle with 2 equal sides.
A scalene triangle is one type of triangle that will be formed from the given dimensions.
Just the one and it will be an isosceles triangle
There is one equilateral triangle with 3 equal sides of 7in
More than one unique triangle exists with the given side lengths.
None because to form a triangle the sum of its smaller sides must be greater than its largest side
As many as you like but they will all be scalene triangles formed by the given angles that add up to 180 degrees
As many as you like but they will all be scalene triangles from the given interior angles that add up to 180 degrees.