To determine the number of triangles that can be formed with side lengths of 4m, 4m, and 7m, we can use the triangle inequality theorem. For a triangle to exist, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4m + 4m = 8m, which is greater than 7m. Therefore, a triangle can be formed. Since all three sides are equal in length, this triangle is an equilateral triangle. So, there is only one triangle that can be formed with side lengths of 4m, 4m, and 7m.
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A triangle with two equal sides is an isosceles triangle and you can have as many as you like.
As many as you like but they will all be scalene triangles formed by the given angles that add up to 180 degrees
There is only one equilateral triangle with a perimeter of 60 units. Its side lengths are integers.
It depends on the question you are asked. There are never 3 distinct triangles; there can only be 0,1, or 2 distinct triangles. Idk if that helps because the question is kinda general.
There is only one triangle. Or two if you count its mirror image as a different triangle.
Yes, any length - from virtually zero to that of the diameter.