you atart at 405 and add 9 from then on.
An infinite number.
The first whole number divisible by 3 is 102 and the last one 399. Let n be the number of whole numbers between 102 and 399 102 + (n - 1)x3 = 399 (this is an arithmetic progression) Solving n, n-1 = (399 - 102)/3 = 99 n = 100 Since even whole numbers among these 100 will be divisible by 6, the number not divisible is half of 100, i.e. 50. regards, lpokbeng
33 numbers between 1 and 100 are divisible by 3.
There are many numbers between 500 and 1000 divisible by 3 and 9. Any number divisible by 9 is divisible by 3. How about 900?
48 is divisible by ten factors. There is an infinite amount of numbers divisible by 48.
There are 5 multiples of 18 between 200 and 300. (An even number divisible by 9 is any number divisible by 18).
Two of them.
There are 33 such numbers.
9 of them.
251
There are infinitely many numbers divisible by 63, just multiply 63 by any whole number and you'll get one.