This sounds like you're asking about a 10-digit binary number.
Each position has two possibilities. For every position, you add a power of two.
So 10 positions = 2^10 = 1024 possibilities.
To show you how it works, I will demonstrate with a 3-digit binary number.
000
001
010
011
100
101
110
111
As you can see, there are eight (8) possibilities with three binary digits.
3 positions = 2^3 = 8.
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how many numbers exactly have 4 digits ? 8900, 8999, 9000, 9999
I believe here are 51 such numbers.
hjust do whatever
The standard form of a whole number is when a whole number is written in digits with commas separating the digits into groups of three starting from right to left
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