Without knowing the width of the shovel, it's not possible to calculate
the volume of the hole.
But whatever its volume is, there's no dirt at all in the hole.
None. Once you dig it, it is out of the hole, not in it.
It would depend on the size of the aggregate
There's no way of telling. 18,000 gallons is roughly 2400 cubic feet. If the pool was six feet deep, the surface area would be 400 square feet. if the pool was eight feet deep, the surface area would be 300 square feet. It could be almost any configuration.
You need to know how deep you want the sand.
If the container is 1 inch deep, the area is 1 square foot.
None, if it is a hole.
None. Once you dig it, it is out of the hole, not in it.
None Or it wouldn't be a hole.
1.6042 square feet (rounded)
One cubic meter cannot be "converted" to a square measure unless we know how "deep" it is being spread. For example, if it is one meter deep, then it would cover one square meter; but if it is two meters deep, then it would cover half that area. If it were, say, 1 cm deep, then it could cover a million square centimeters (100 x 100 x 100).
You are mixing volume (square yard) and area (length x width). How deep do you want the dirt? One foot deep you need about 80 square yards of dirt.
One cubic yard of mulch will cover approximately 160 square feet at 2" deep, so you would need approximately two cubic yards of mulch to cover 271 square feet at 2" deep.
That depends entirely on what kind of sand how deep you spread it. As an approximation, you could assume a bulk density for dry sand of about 110 lb/ft3. One ton (2000 lb) of sand would thus be about 18.18 ft3 or 0.673 yd3. If you spread it 6 inches deep you could cover about 4 square yards. At a foot deep, you would cover 2 square yards. At 3 inches deep you would cover 8 square yards. At 1 inch deep you would cover 24 square yards Reported bulk densities for sand range from 78 lb/ft3 for molding sand to 130 lb/ft3 for moist sand.
It would depend on the size of the aggregate
How Electron confinement in infinitely deep square well
22x32x1foot deep=sqft
There's no way of telling. 18,000 gallons is roughly 2400 cubic feet. If the pool was six feet deep, the surface area would be 400 square feet. if the pool was eight feet deep, the surface area would be 300 square feet. It could be almost any configuration.