Well, honey, if you want to make 243 divisible by 10, you need to add 7 to it. Why 7, you ask? Because 243 + 7 = 250, and 250 is divisible by 10. So, go ahead and sprinkle that 7 on top like the cherry on a sundae.
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Oh, dude, you just need to add 7 to 243 to make it divisible by 10. It's like, basic math, you know? So, 243 + 7 = 250, and 250 is totally divisible by 10. Easy peasy lemon squeezy!
To make 243 divisible by 10, you need to add 7. Divisibility by 10 means the number must end in 0, which 243 does not. By adding 7 to 243, you get 250, which is divisible by 10.
The next nearest number divisible evenly by 10 would be 250 so you need to add 7 ro 243
To make 243 divisible by 10, we need to find the nearest multiple of 10. The nearest multiple of 10 less than 243 is 240. To make 243 divisible by 10, we need to add 240 + 3, which equals 243. Therefore, we need to add 3 to 243 to make it divisible by 10.
If a number is divisible by 4, the last two digits are divisible by 4. For example, the number 314 is not divisible by 4, but 316 is divisible by 4, because 16 is divisible by 4.
what least number must be subtracted from 13081 to get a number exactly divisible by 87
To find the smallest sum of money that can be added to 2.45 to make it exactly divisible by 9, we first need to determine the remainder when 2.45 is divided by 9. 2.45 can be written as 245/100. When 245 is divided by 9, the remainder is 8. To make 2.45 exactly divisible by 9, we need to add the difference between 9 and the remainder, which is 9 - 8 = 1. Therefore, the smallest sum of money that can be added to 2.45 to make it exactly divisible by 9 is $0.01.
To determine if 1728 is divisible by 6, we need to check if the sum of its digits is divisible by 3 and if it is an even number. The sum of the digits of 1728 is 1+7+2+8=18, which is divisible by 3. Additionally, the last digit of 1728 is 8, which is an even number. Therefore, 1728 is divisible by 6.