To find the number that can be added to 368 to make it divisible by 27, you need to first determine the remainder when 368 is divided by 27. You can do this by finding the modulus of 368 divided by 27, which is 17. To make 368 divisible by 27, you need to add the difference between 27 and the remainder (27 - 17 = 10). Therefore, you would need to add 10 to 368 to make it divisible by 27.
To find the least number that must be added to 37969 to make it exactly divisible by 65, first, we calculate the remainder when 37969 is divided by 65. The remainder is 44 (since 37969 ÷ 65 = 584 with a remainder of 44). To make it divisible by 65, we need to add (65 - 44 = 21). Thus, the least number that must be added is 21.
To find the least number that should be added to 924 to make it exactly divisible by 48, we need to find the remainder when 924 is divided by 48. The remainder is 12. Therefore, the least number that should be added to 924 to make it exactly divisible by 48 is 48 - 12, which equals 36.
To determine the smallest number that must be added to 5621 to make it divisible by 12, we first find the remainder of 5621 when divided by 12. Dividing 5621 by 12 gives a remainder of 5. Therefore, to make 5621 divisible by 12, we need to add (12 - 5 = 7). Thus, the smallest number to add is 7.
To determine the smallest number that must be added to 403 to make it divisible by 8, first find the remainder when 403 is divided by 8. The remainder is 3 (since 403 ÷ 8 = 50 with a remainder of 3). To make it divisible by 8, you need to add 5 (8 - 3 = 5). Therefore, the smallest number to add is 5.
To find the least number that must be added to 1056 to make it divisible by 23, first, we divide 1056 by 23, which gives us a quotient of 45 with a remainder of 21. Since 1056 is 21 more than a multiple of 23, we need to add ( 23 - 21 = 2 ) to 1056. Therefore, the least number that must be added to 1056 to make it exactly divisible by 23 is 2.
339 + 1 = 340,which is exactly divisible.
To find the least number that must be added to 37969 to make it exactly divisible by 65, first, we calculate the remainder when 37969 is divided by 65. The remainder is 44 (since 37969 ÷ 65 = 584 with a remainder of 44). To make it divisible by 65, we need to add (65 - 44 = 21). Thus, the least number that must be added is 21.
To find the least number that should be added to 924 to make it exactly divisible by 48, we need to find the remainder when 924 is divided by 48. The remainder is 12. Therefore, the least number that should be added to 924 to make it exactly divisible by 48 is 48 - 12, which equals 36.
To determine the smallest number that must be added to 5621 to make it divisible by 12, we first find the remainder of 5621 when divided by 12. Dividing 5621 by 12 gives a remainder of 5. Therefore, to make 5621 divisible by 12, we need to add (12 - 5 = 7). Thus, the smallest number to add is 7.
To determine the smallest number that must be added to 403 to make it divisible by 8, first find the remainder when 403 is divided by 8. The remainder is 3 (since 403 ÷ 8 = 50 with a remainder of 3). To make it divisible by 8, you need to add 5 (8 - 3 = 5). Therefore, the smallest number to add is 5.
the rule for divisibility by 9 is that the sum of all digits of the number should should be divisible by 9. So, 3+9+0+6+5= 23. To make is divisible by 9, we think of 27 (as the next number divisible by 9) and that means if we add 4 to any digit of the number, it will be divisible. 39069/9=4341
To find the least number that must be added to 1056 to make it divisible by 23, first, we divide 1056 by 23, which gives us a quotient of 45 with a remainder of 21. Since 1056 is 21 more than a multiple of 23, we need to add ( 23 - 21 = 2 ) to 1056. Therefore, the least number that must be added to 1056 to make it exactly divisible by 23 is 2.
It is 8961 - W*int(8961/W)
It is: 36 and so 960/48 = 20
342 is divisible by 6 and not 5.Numbers divisible by 5 end in zeros or fivesNumbers divisible by 6 have a slightly more complicated rule. If, when the individual digits are added together and they make a multiple of 3, see if the number is even. If so, and the digits add up to a multiple of 3, then the number is a divisible by 6.
6. To check for divisibility by 9, add the digits of the number together and if the sum is divisible by 9, then the original number is divisible by 9. If the test is repeated on the sum(s) until a single digit remains, then this is the remainder when the original number is divided by 9. Subtracting this remainder from 9 will give the smallest number that needs to be added to to the original number to make it divisible by 9. For 75: 7 + 5 = 12 1 + 2 = 3 so 75 ÷ 9 has a remainder of 3, therefore add 9 - 3 = 6 to 75 to make it divisible by 9. (75 + 6 = 81 = 9 x 9).
To determine what number makes 371 divisible by 3, we need to sum the digits of 371: 3 + 7 + 1 = 11. To be divisible by 3, the sum of the digits must also be divisible by 3. Since 11 is not divisible by 3, we need to find the number that, when added to 11, results in a sum divisible by 3. The next multiple of 3 greater than 11 is 12, so the number that makes 371 divisible by 3 is 1.