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To find the number that can be added to 368 to make it divisible by 27, you need to first determine the remainder when 368 is divided by 27. You can do this by finding the modulus of 368 divided by 27, which is 17. To make 368 divisible by 27, you need to add the difference between 27 and the remainder (27 - 17 = 10). Therefore, you would need to add 10 to 368 to make it divisible by 27.
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What least number must be added to 308 to make it divisible by 19?
To find the least number that must be added to 308 to make it divisible by 19, we first divide 308 by 19. The division gives a quotient of 16 with a remainder of 4, since ( 19 \times 16 = 304 ). To make 308 divisible by 19, we need to add ( 19 - 4 = 15 ). Thus, the least number that must be added is 15.
What least number must be added to 37969 to get a number exactly divisible by 65?
To find the least number that must be added to 37969 to make it exactly divisible by 65, first, we calculate the remainder when 37969 is divided by 65. The remainder is 44 (since 37969 ÷ 65 = 584 with a remainder of 44). To make it divisible by 65, we need to add (65 - 44 = 21). Thus, the least number that must be added is 21.
What is the least number that should be added to 924 to make it exactly divisible by 48?
To find the least number that should be added to 924 to make it exactly divisible by 48, we need to find the remainder when 924 is divided by 48. The remainder is 12. Therefore, the least number that should be added to 924 to make it exactly divisible by 48 is 48 - 12, which equals 36.
What is the smallest number which must be added to 403 to make it divisible by 8?
To determine the smallest number that must be added to 403 to make it divisible by 8, first find the remainder when 403 is divided by 8. The remainder is 3 (since 403 ÷ 8 = 50 with a remainder of 3). To make it divisible by 8, you need to add 5 (8 - 3 = 5). Therefore, the smallest number to add is 5.
What is the smallest number that must be added to 5621 to make a that is divisible by 12?
To determine the smallest number that must be added to 5621 to make it divisible by 12, we first find the remainder of 5621 when divided by 12. Dividing 5621 by 12 gives a remainder of 5. Therefore, to make 5621 divisible by 12, we need to add (12 - 5 = 7). Thus, the smallest number to add is 7.
What is the smallest number that must be added to 339 to make it exactly divisible?
339 + 1 = 340,which is exactly divisible.
What least number must be added to 308 to make it divisible by 19?
To find the least number that must be added to 308 to make it divisible by 19, we first divide 308 by 19. The division gives a quotient of 16 with a remainder of 4, since ( 19 \times 16 = 304 ). To make 308 divisible by 19, we need to add ( 19 - 4 = 15 ). Thus, the least number that must be added is 15.
What least number must be added to 37969 to get a number exactly divisible by 65?
To find the least number that must be added to 37969 to make it exactly divisible by 65, first, we calculate the remainder when 37969 is divided by 65. The remainder is 44 (since 37969 ÷ 65 = 584 with a remainder of 44). To make it divisible by 65, we need to add (65 - 44 = 21). Thus, the least number that must be added is 21.
What is the least number that should be added to 924 to make it exactly divisible by 48?
To find the least number that should be added to 924 to make it exactly divisible by 48, we need to find the remainder when 924 is divided by 48. The remainder is 12. Therefore, the least number that should be added to 924 to make it exactly divisible by 48 is 48 - 12, which equals 36.
What is the smallest number which must be added to 403 to make it divisible by 8?
To determine the smallest number that must be added to 403 to make it divisible by 8, first find the remainder when 403 is divided by 8. The remainder is 3 (since 403 ÷ 8 = 50 with a remainder of 3). To make it divisible by 8, you need to add 5 (8 - 3 = 5). Therefore, the smallest number to add is 5.
What is the smallest number that must be added to 5621 to make a that is divisible by 12?
To determine the smallest number that must be added to 5621 to make it divisible by 12, we first find the remainder of 5621 when divided by 12. Dividing 5621 by 12 gives a remainder of 5. Therefore, to make 5621 divisible by 12, we need to add (12 - 5 = 7). Thus, the smallest number to add is 7.
What number should be added to 39065 to make it divisible by 9?
the rule for divisibility by 9 is that the sum of all digits of the number should should be divisible by 9. So, 3+9+0+6+5= 23. To make is divisible by 9, we think of 27 (as the next number divisible by 9) and that means if we add 4 to any digit of the number, it will be divisible. 39069/9=4341
What least number must be added to 1056 to get a number a exactly divisible by 23?
To find the least number that must be added to 1056 to make it divisible by 23, first, we divide 1056 by 23, which gives us a quotient of 45 with a remainder of 21. Since 1056 is 21 more than a multiple of 23, we need to add ( 23 - 21 = 2 ) to 1056. Therefore, the least number that must be added to 1056 to make it exactly divisible by 23 is 2.
What least number must be added to 8961 to make it exactly divisible by W?
It is 8961 - W*int(8961/W)
What is the least number that should be added toto 924 to make it divisible by 48?
It is: 36 and so 960/48 = 20
What least number should be added to 39065 to make it divisible by 9?
To determine the least number that should be added to 39065 to make it divisible by 9, we first calculate the sum of the digits of 39065: 3 + 9 + 0 + 6 + 5 = 23. The nearest multiple of 9 greater than 23 is 27. Therefore, we need to add 27 - 23 = 4 to 39065. Thus, the least number to be added is 4.
What is the smallest number whhich must be added to 75 to make a number exactly divisible by 9?
6. To check for divisibility by 9, add the digits of the number together and if the sum is divisible by 9, then the original number is divisible by 9. If the test is repeated on the sum(s) until a single digit remains, then this is the remainder when the original number is divided by 9. Subtracting this remainder from 9 will give the smallest number that needs to be added to to the original number to make it divisible by 9. For 75: 7 + 5 = 12 1 + 2 = 3 so 75 ÷ 9 has a remainder of 3, therefore add 9 - 3 = 6 to 75 to make it divisible by 9. (75 + 6 = 81 = 9 x 9).
