To calculate the vertical drop over a given horizontal distance due to a slope, we use the formula: vertical drop = horizontal distance * tan(slope angle). Given a 3-degree slope over 1 meter, the vertical drop would be 1 meter * tan(3 degrees), which is approximately 0.0524 meters or 5.24 centimeters. This means that for every 1 meter of horizontal distance, the elevation would decrease by about 5.24 centimeters.
30cm
10*sin(1) metres = 0.175 metres = 17.5 cm.
Fall = 1 metre*arctan(25 deg) = 1 metre*0.466 = 0.466 m or 46.6 cm approx
3 degrees is a slope of 5.24 centimeters per meter. (rounded)
There are 34.9 mm of fall.
Approx 0.087 metres.
30cm
Approx 0.087 metres.
Approx 0.087 metres.
To calculate the fall (or drop) of an 8-degree roof over a distance of 1 meter, you can use the tangent function from trigonometry. The formula is: fall = distance × tan(angle). For an 8-degree angle, the fall is approximately 1 meter × tan(8°), which equals about 0.14 meters, or 14 centimeters.
To calculate the fall over a 5-degree roof pitch over a 6-meter span, you can use the tangent of the angle. The height (fall) is equal to the length multiplied by the tangent of the angle: ( \text{Fall} = 6 , \text{m} \times \tan(5^\circ) ). This results in approximately 0.52 meters, or 52 centimeters of fall over the 6-meter length.
10*sin(1) metres = 0.175 metres = 17.5 cm.
Well, darling, if you have a 4-degree roof pitch over 1 meter, you're looking at a fall of about 7.1 centimeters. So, make sure you bring a ruler and a level to get that slope just right. And remember, measure twice, cut once!
It is 52 mm.
Fall = 1 metre*arctan(25 deg) = 1 metre*0.466 = 0.466 m or 46.6 cm approx
1 degree slope = 1.746 centimeter rise or fall in 1 meter of run.
3 degrees is a slope of 5.24 centimeters per meter. (rounded)