To calculate the vertical drop over a given horizontal distance due to a slope, we use the formula: vertical drop = horizontal distance * tan(slope angle). Given a 3-degree slope over 1 meter, the vertical drop would be 1 meter * tan(3 degrees), which is approximately 0.0524 meters or 5.24 centimeters. This means that for every 1 meter of horizontal distance, the elevation would decrease by about 5.24 centimeters.
30cm
10*sin(1) metres = 0.175 metres = 17.5 cm.
Fall = 1 metre*arctan(25 deg) = 1 metre*0.466 = 0.466 m or 46.6 cm approx
There are 34.9 mm of fall.
3 degrees is a slope of 5.24 centimeters per meter. (rounded)
Approx 0.087 metres.
30cm
Approx 0.087 metres.
Approx 0.087 metres.
10*sin(1) metres = 0.175 metres = 17.5 cm.
1 degree slope = 1.746 centimeter rise or fall in 1 meter of run.
Fall = 1 metre*arctan(25 deg) = 1 metre*0.466 = 0.466 m or 46.6 cm approx
It is 52 mm.
Oh, dude, you're hitting me with the math questions now? Alright, let's see... So, if we have a 1.5 degree angle over 1 meter, you'd use some trigonometry magic and find out it falls about 26.2 millimeters. But hey, who's really counting, right? Like, just eyeball it and call it a day.
There are 34.9 mm of fall.
Approx 0.087 metres.
It is 32 cm.