To find the fall of a 5-degree roof over 1 meter, you can use basic trigonometry. The vertical drop (fall) can be calculated using the sine function: fall = 1 meter × sin(5 degrees). This results in a vertical drop of approximately 0.087 meters, or 8.7 centimeters.
It is 32 cm.
Approx 0.087 metres.
Approx 0.087 metres.
To calculate the fall (or rise) for an 11-degree roof over 1 meter, you can use the tangent of the angle. The fall can be calculated as: fall = 1 meter * tan(11 degrees). This gives approximately 0.193 meters, or 19.3 centimeters of fall over 1 meter of horizontal distance.
Approx 98 centimetres.
Fall = 1 metre*arctan(25 deg) = 1 metre*0.466 = 0.466 m or 46.6 cm approx
160mm
To determine the fall (or slope) of a 2-degree roof over a 4-meter span, you can use the formula for rise: rise = distance × tan(angle). For a 2-degree angle, the rise is approximately 0.07 meters (or 7 centimeters) over 4 meters. Therefore, the fall over a 4-meter length at a 2-degree slope is about 7 centimeters.
Approx 0.087 metres.
30cm
It is 32 cm.
Approx 0.087 metres.
Approx 0.087 metres.
To calculate the fall (or rise) for an 11-degree roof over 1 meter, you can use the tangent of the angle. The fall can be calculated as: fall = 1 meter * tan(11 degrees). This gives approximately 0.193 meters, or 19.3 centimeters of fall over 1 meter of horizontal distance.
Approx 98 centimetres.
To calculate the fall (or drop) of an 8-degree roof over a distance of 1 meter, you can use the tangent function from trigonometry. The formula is: fall = distance × tan(angle). For an 8-degree angle, the fall is approximately 1 meter × tan(8°), which equals about 0.14 meters, or 14 centimeters.
For a roof with a 1.5-degree slope over a distance of 1 meter, the fall can be calculated using basic trigonometry. The vertical drop (fall) is equal to the distance multiplied by the sine of the angle. Therefore, the fall is approximately 0.026 meters, or 26 millimeters.