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If the half-life of bromine is 25 minutes, than in 75 minutes three half lives would have passed. If you started with a 4.0 mg sample, than after three half-lives only 0.50 mg would remain. Because you are dealing with a whole number of half lives, all you have to do is divide 4.0 by 2 three time. Alternatively, you could multiply 4.0 by one half raised to the third power. This would look like this when entered into a calculator: 4.0 X (0.5^3) = 0.5

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Q: How much of a 4.0 mg sample is still active after 75 min if the half-life of bromine-74 is 25 min?
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