Depends on the time of day (the angle of the sun).
Think of the person as being at a right angle to the ground, and the shadow being the other side. The distance from the person's head to the end of the shadow is the hypotenuse. (a^2 + b^2= c^2) a= height of person, b= shadow.
If you have the angle of the sun to the ground, you can use Sine/ Cosine to calculate the length.
A 1 foot shadow I think.
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
The tree is 34.5 feet tall because tangent ratio of 34.5/24 = 5.75/4
A stick is 6/4.5 = 4/3 times its shadow. So the tree is 4/3*25 = 33.3... feet or 33 ft 4 inches tall.
The man is twice as high as his shadow. Therefore, the tree must also be twice as high as its shadow, which would make the tree 40 feet tall.
63 feet
If a 27 ft tall pole casts an 18 foot shadow, a 63 ft tall pole casts an x foot shadow.Put 27/18 and 63/x.Cross multiply, get 27x=1134Divide by 27 on both sides, a 63 foot tall pole casts a 42 foot long shadow.
121.3yd
15 feet high
39
A 1 foot shadow I think.
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
The tree is 33 feet tall. Use ratios to solve this equation. 6/4 = n/22 6 x 22 = 4n 4n = 132 n = 33
2
x/85 = 6/17 30 ft.
The tree is 34.5 feet tall because tangent ratio of 34.5/24 = 5.75/4
21