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IS it possible to have a figure with an area of 18 square units and a perimeter of 28 units?
Wiki User
∙ 12y ago
Yes. A rectangle 12.568 x 1.432 has a perimeter of 28 and an area of 17.997, all correct to the third decimal place.
Calculation: length + width = 14, length x width = 18
width = 14 - length, so length x (14 - length) = 18
so (14 x length) - (length x length) = 18
which is: length squared - 14 x length + 18 = 0
Using the quadratic formula (- b +/- sqrt (b squared - 4 times a times c) where a = 1, b = 14 and c = 18 all divided by twice a) gives the solutions 25.136/2 and 2.864/2
Wiki User
∙ 12y ago
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