Prime factorization of 115 is: 5x23 Prime factors are the prime numbers multiplied with each other that together form the original numerical value. Prime numbers are numbers that have no factors besides one and itself. The first prime number is 2, then 3, 5, 7, 11, 13, and so on. Sometimes one may have a number that has multiple same prime numbers for its prime factorization; for example the prime factorization of 256 is 2x2x2x2x2x2x2x2
To find the smallest value of k when 882k is a cube, we need to factor out the cube from 882k. The prime factorization of 882 is 2 x 3^2 x 7^2. For 882k to be a cube, we need to find the smallest value of k such that the exponent of each prime factor in the prime factorization of 882k is a multiple of 3. Therefore, the smallest value of k would be 2^2 x 3 x 7 = 84.
7 and 3 are two prime numbers that add up to 10 If you meant 73 then that is also a prime number because it has only two factors which are itself and one.
Value must be correct
What effect do interest rates have on the calculation of future and present value, how does the length of time affect future and present value, how do these two factors correlate.
The sum of the prime factors of 6 is closest in value to the composite number 6.
13 is a Prime number whose only factors are itself and one
1
As a product of its prime factors in exponents it is: 22*53 = 500
It is not possible to answer the question without the numerical value of Y.
Prime factorization of 115 is: 5x23 Prime factors are the prime numbers multiplied with each other that together form the original numerical value. Prime numbers are numbers that have no factors besides one and itself. The first prime number is 2, then 3, 5, 7, 11, 13, and so on. Sometimes one may have a number that has multiple same prime numbers for its prime factorization; for example the prime factorization of 256 is 2x2x2x2x2x2x2x2
To find the smallest value of k when 882k is a cube, we need to factor out the cube from 882k. The prime factorization of 882 is 2 x 3^2 x 7^2. For 882k to be a cube, we need to find the smallest value of k such that the exponent of each prime factor in the prime factorization of 882k is a multiple of 3. Therefore, the smallest value of k would be 2^2 x 3 x 7 = 84.
That depends on the value of y but 40 as a product of its prime factors is 2*2*2*5 or as 23*5
To find the prime factors of any number then divide the number by prime numbers of increasing value. When a prime number wholly divides the original number repeat the process with the same prime number but each time with the new quotient until complete division does not occur. Repeat with a prime number of higher value until the final quotient is 1. Using this process gives the prime factors of 374 as 2, 11 and 17.
5
5 is a prime number because it has only two factors which are itself and one
13 is a prime number because it has only two factors which are itself and one.