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To find the smallest value of k when 882k is a cube, we need to factor out the cube from 882k. The prime factorization of 882 is 2 x 3^2 x 7^2. For 882k to be a cube, we need to find the smallest value of k such that the exponent of each prime factor in the prime factorization of 882k is a multiple of 3. Therefore, the smallest value of k would be 2^2 x 3 x 7 = 84.
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ViviFactor the number 882, until you get prime factors. See what prime factors are missing to complete a cube (each Prime number has to be to the power 3, 6, etc.). Multiply those missing factors, to get "k".
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What is the smallest integer k such that 756k is a perfect cube?
k = 98. In the prime factorization (in power format) of a perfect cube, every prime must be to the power of a multiple of 3. 756 = 2^2 x 3^3 x 7 Thus the smallest perfect cube that is a multiple of 756 is 2^3 × 3^3 × 7^3; to obtain this need to multiply 756 by 2^1 × 3^0 × 7^2 = 98 Thus the smallest k to make 756k a perfect prime is k = 98.
What is the smallest integer k such that 540k is a cube number?
You can factor 540 into prime factors. Then, for each prime factor that doesn't appear 3, 6, 9, ... times, add additional factors to complete a multiple of 3. These factors will make up the number "k".
The cube of the product of k and m?
(k*m)3 = k3*m3
Which of these is the smallest k k plus 1 kr br-1?
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Which of these is the smallest Br-1 K Kr Kr plus 1?
k+1
