To find the smallest value of k when 882k is a cube, we need to factor out the cube from 882k. The prime factorization of 882 is 2 x 3^2 x 7^2. For 882k to be a cube, we need to find the smallest value of k such that the exponent of each prime factor in the prime factorization of 882k is a multiple of 3. Therefore, the smallest value of k would be 2^2 x 3 x 7 = 84.
Factor the number 882, until you get prime factors. See what prime factors are missing to complete a cube (each Prime number has to be to the power 3, 6, etc.). Multiply those missing factors, to get "k".
k = 98. In the prime factorization (in power format) of a perfect cube, every prime must be to the power of a multiple of 3. 756 = 2^2 x 3^3 x 7 Thus the smallest perfect cube that is a multiple of 756 is 2^3 × 3^3 × 7^3; to obtain this need to multiply 756 by 2^1 × 3^0 × 7^2 = 98 Thus the smallest k to make 756k a perfect prime is k = 98.
You can factor 540 into prime factors. Then, for each prime factor that doesn't appear 3, 6, 9, ... times, add additional factors to complete a multiple of 3. These factors will make up the number "k".
(k*m)3 = k3*m3
0
The square of r increased by a quantity that is fifty times the cube of k can be written as r squared + 50 (k cubed). It cannot be solved any further.
70
k = 98. In the prime factorization (in power format) of a perfect cube, every prime must be to the power of a multiple of 3. 756 = 2^2 x 3^3 x 7 Thus the smallest perfect cube that is a multiple of 756 is 2^3 × 3^3 × 7^3; to obtain this need to multiply 756 by 2^1 × 3^0 × 7^2 = 98 Thus the smallest k to make 756k a perfect prime is k = 98.
You can factor 540 into prime factors. Then, for each prime factor that doesn't appear 3, 6, 9, ... times, add additional factors to complete a multiple of 3. These factors will make up the number "k".
No, there is not. Suppose k lay claim to be the smallest integer. Then k-1 is and integer and it is smaller than k. So k cannot be the smallest.
There is no smallest whole number. Assume that k is the smallest whole number.Consider (k-1).It is smaller than k and it is a whole number.This contradicts the assumption that k is the smallest whole number.Such a number does not exist.
(sinx-c0sx)(1-sinxcosx)=sin cube x+ cos cube X(sinx-c0sx)(1-sinxcosx)=9sin cube x find angle betwn 0 to 360Q 2 complete UPTO 4 term (k+x)power 8if x squre = x cube find the value of k....
Factor 756 into prime factors. Then add additional prime factors, such that each prime factor occurs a number of times that is a multiple of 3. The product of the additional prime factors is "k".
(k*m)3 = k3*m3
K+
0
The Wren.
The answer depends on how many 1 cm cubes you start off with. If you had n cubes then the largest hollow cube is a k-cube where k^3 <= 6n^2 - 12n + 8