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f(7) = -9.
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What is the vertical asymptote of X minus 7 divided by negative 2X plus 7 times 2X plus 5?
f(x)= (x-7) /(-2x+7)(2x+5) set -2x+7=0 -2x=-7 x=7/2 set 2x+5=0 2x=-5 x=-5/2 x=7/2 and x=-5/2 are vertical asymptotes.
For f x 2x plus 1 and g x x2-7 find f g x?
f(x) = 2x + 1 g(x) = x^2 - 7 So f*g(x) = f(g(x)) = f(x^2 - 7) = 2*(x^2 - 7) + 1 = 2*x^2 - 14 + 1 = 2*x^2 - 13
If f(x)2x-1 and g(x) x plus 2 fimd (f plus g)(x)?
h(x)=3x-4
How do you rewrite as a function of x using function notation for 2x plus 3y equals 4?
If 2x + 3y = 4, y= (4 - 2x)/3. In function notation, f(x) = (4 - 2x)/3.
What can you say about the end behavior of the function f(x)- In (2x) plus 4?
You cannot because the function is not well-defined. There is no equality symbol, the function In(2x) is not defined.
What is x when f of x equals -7 and f of x is defined to be 2x plus 8?
f(x) = 2x + 8 f(x) = -7 → 2x + 8 = -7 → 2x = -15 → x = -7½ = -7.5
When x3 plus 3x2-2x plus 7 is divided by x plus 1 the remainder is?
== == Suppose f(x) = x3 + 3x2 - 2x + 7 divisor is x + 1 = x - (-1); so rem = f(-1) = 11
What is the vertical asymptote of X minus 7 divided by negative 2X plus 7 times 2X plus 5?
f(x)= (x-7) /(-2x+7)(2x+5) set -2x+7=0 -2x=-7 x=7/2 set 2x+5=0 2x=-5 x=-5/2 x=7/2 and x=-5/2 are vertical asymptotes.
How do you rewrite this equation so that y is a function of x 2x plus y equals 7?
y=f(x)= x(2x+y)=7 f(x)=2x^2 +xy -7 = 0 y=2x^2 +xy -7 y-xy -7 + 2x^2 = 0 y(1-x)=2x^2-7 y=(2x^2-7) / (1-x) Excuse the working. Y equals 2 X squared minus 7 all divided by 1-X
For f x 2x plus 1 and g x x2-7 find f g x?
f(x) = 2x + 1 g(x) = x^2 - 7 So f*g(x) = f(g(x)) = f(x^2 - 7) = 2*(x^2 - 7) + 1 = 2*x^2 - 14 + 1 = 2*x^2 - 13
How do i solve his algebra problem My homework is Function Notation The first problem is F 2x and what he gave us is F x 2x plus 5?
The equation F X 2X plus 5 equals 0.5. This is a algebra math problem.
F the expression 2x plus 6 equals 20 what is the value of x?
Subtract 6 from each side: 2x = 14; divide each side by 2: x = 7
If fx -2x 1 and gx -4x then gf4?
f(x) = -2x + 1; g(x) = -4x; g(f(4)) = ? Solution: (g ° f)(4) = g(f(4)) = g(-7) = 28 f(x) = -2x + 1 f(4) = -2(4) + 1 f(4) = -7 g(x) = -4x g(-7) = -4(-7) g(-7) = 28
If f(x)x to the power of 2 plus 2x-3 find f(2)?
It is 5.
If f(x)xto the power of 2 plus 2x-3 find f(2)?
It is 5.
How do you find the Fog-2 of FofX equals 2x - 7 and GofX -4x plus 6 I tried it but got this crazy answer Please help?
f(x) = 2x - 7g(x) = -4x + 6f.g(-2) = f(g(-2))g(-2) = -4*-2 + 6 = 8 + 6 = 14so f.g(-2) = f(14) = 2*14 - 7 = 28 - 7 = 21.
What is f if f plus 7 equals 2 plus 10?
f+7=12 is the equation so, f=5
