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The expected number is 12/7 = 1.29 approx.

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Q: If 3 balls are drawn from a bag containing 3 red balls and 4 blue balls what is the expected number of red balls drawn?
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One ball is drawn at random from a bag containing 17 red balls and 4 white balls what is the probability that the ball is red?

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A bag containing 4 green 6 black 7 white balls a ball is drawn at randomly probability of finding 2 red balls?

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A box contains 4 red balls and 2 black balls Three balls are drawn with replacement Let the random variable X be the number of red balls obtained?

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A box contains 75 balls numbered from 1 to 75 If 7 balls are drawn with replacement what is the probability that at least two of them have the same number?

25.1%The probability of having at least two same number balls when 7 balls are drawn withreplacement from a box containing 75 numbered balls from 1 to 75 is calculated asfollows:We calculate the probability of drawing 7 times a ball (with replacement) and havingall different numbers. Then we subtract this value from 1. This will be the probabilityof all the possibilities of combinations of 7 numbers where at least two are repeated.1.- For the 1st ball the options are 75/75.2.- For the 2nd ball the options for not repeating the 1st number are 74/75.3.- For the 3rd ball the options for not repeating the previous two numbers are 73/75.4.- For the 4th ball the options for not repeating the previous three numbers 72/75.5.- For the 5th ball ........................................................................... 71/75.6.- For the 6th ball ........................................................................... 70/75.7.- For the 7th ball ........................................................................... 69/75.The probability of drawing seven balls (with replacement) having all different numbersis: 75/75(74/75)(73/75)(72/75)(71/75)(70/75)(69/75) = 0.749419476...The probability of having at least two same number balls when 7 balls are drawn with replacement from the given box is:P = 1 - 0.749419476... = 0.250580524...≈ 25.1%


What is the experimental probability that a piece of paper randomly drawn from the bowl will have the number 35 written on it?

To get the EXPERIMENTAL probability, you'll have to actually carry out the experiment. The EXPECTED probability is equal to a fraction; the numerator will be the number of pieces of papers that have the number 35, the denominator will be the total number of pieces. If you repeat the experiment often, you can expect the experimental probability to be close to the expected probability.


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No tangent No tangent


If an urn contains 6 yellow balls 3 red balls and 5 blue balls If 2 balls are drawn without replacement what is the probability of drawing 2 yellow balls?

The probability is (6/14)*(5/13) = 30/182 = 0.1648 approx.


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28989675, based on the following criteria: Combination means order does not matter, and there is no repetition allowed (like drawing lotto balls, once a number is drawn, then it cannot be drawn again, and order that the balls are drawn doesn't matter) The formula for this is Combination of n items, taken rat a time.C(n,r) = n! / (r!(n-r)!), where n = 55 and r = 6, in this case. See related link on MathsIsFun.com