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What is the number of diagonals drawn from one vertex on a 13-gon?
There are 10 possible diagonals drawn from one vertex of the 13-gon which divide it into 11 nonoverlapping triangles.
What is the diagonal of 16-gon from one vertex?
If you mean "How many diagonals can be drawn from one vertex of a figure with 16 sides", the formula is n-3, where "n" being the number of sides of the figure. So 16-3 = 13 diagonals that can be drawn from one vertex.
There are 6 diagonals that can be drawn from one vertex of an octagon?
No.
How many diagonals can be drawn from one vertex of dodecagon?
12-3 = 9
How many diagonals can be drawn from one vertex of a decagon?
Oh, dude, a decagon has 10 sides, right? So, if you pick one vertex and want to draw diagonals, you can draw diagonals to all the other vertices except the adjacent ones, which are already sides. So, you can draw 7 diagonals from that one vertex. Math can be fun, like a puzzle... or a headache, depending on how you look at it.
What statement can you make about the number of diagonals that can be drawn from one vertex in a polygon?
Number of sides minus two equals number of diagonals drawn from one vertex.
What is the number of diagonals drawn from one vertex on a 13-gon?
There are 10 possible diagonals drawn from one vertex of the 13-gon which divide it into 11 nonoverlapping triangles.
How many diagonals can you drawn from one vertex in a 35 sided polygon?
In a polygon with n sides, the number of diagonals that can be drawn from one vertex is given by the formula (n-3). Therefore, in a 35-sided polygon, you can draw (35-3) = 32 diagonals from one vertex.
How many triangles can be formed by a diagonal drawn from a fixed vertex of a polygon with 17 sides?
In a polygon with 17 sides, a diagonal can be drawn from a fixed vertex to any of the other non-adjacent vertices. From one vertex, there are 14 other vertices (17 total vertices - 1 fixed vertex - 2 adjacent vertices) to which diagonals can be drawn. Each diagonal creates a triangle with the fixed vertex and two of the vertices connected by the diagonal. Therefore, the number of triangles that can be formed is equal to the number of diagonals, which is 14.
What is the number of triangles formed in a decagon when all the diagonals from one vertex are drawn?
8
If all of the diagonals are drawn from a vertex of an n-gon how many triangles are formed?
If all of the diagonals are drawn from a vertex of an octagon, how many triangles are formed
What is the diagonal of 16-gon from one vertex?
If you mean "How many diagonals can be drawn from one vertex of a figure with 16 sides", the formula is n-3, where "n" being the number of sides of the figure. So 16-3 = 13 diagonals that can be drawn from one vertex.
How many diagonals can be drawn from anyone vertex?
Three fewer than the total number of vertices.
There are 6 diagonals that can be drawn from one vertex of an octagon?
No.
How many diagonals can be drawn from one vertex of a polygon of 50 sides?
47 sides. Take a vertex of an n-sided polygon. There are n-1 other vertices. It is already joined to its 2 neighbours, leaving n-3 other vertices not connected to it. Thus n-3 diagonals can be drawn in from each vertex. For n=50, n-3 = 50-3 = 47 diagonals can be drawn from each vertex. The total number of diagonals in an n-sided polygon would imply n-3 diagonals from each of the n vertices giving n(n-3). However, the diagonal from vertex A to C would be counted twice, once for vertex A and again for vertex C, thus there are half this number of diagonals, namely: number of diagonals in an n-sided polygon = n(n-3)/2.
How many diagonals can be drawn from any vertex of a 20-sided polygon?
It is 18 diagonals
What can you say about the relationship of the number of diagonals that can be drawn from each vertex of a polygon?
The formula for the number of diagonals is: 0.5*(n^2-3n) whereas 'n' is the number of sides of the polygon
