The number of Diagonals in one vertex of a Triangle is 0 (zero)..
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There are 10 possible diagonals drawn from one vertex of the 13-gon which divide it into 11 nonoverlapping triangles.
If you mean "How many diagonals can be drawn from one vertex of a figure with 16 sides", the formula is n-3, where "n" being the number of sides of the figure. So 16-3 = 13 diagonals that can be drawn from one vertex.
No.
12-3 = 9
Oh, dude, a decagon has 10 sides, right? So, if you pick one vertex and want to draw diagonals, you can draw diagonals to all the other vertices except the adjacent ones, which are already sides. So, you can draw 7 diagonals from that one vertex. Math can be fun, like a puzzle... or a headache, depending on how you look at it.