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3x = 7y - 2 (subtract 3x and 7y to both sides of the first equation)
9y = 4x + 1

-7y = -3x - 2 (multiply by 4 each term of both sides of the first equation)
9y = 4x + 1 (multiply by 3 each term of both sides of the second equation)

-28y = -12x - 8
27y = 12x + 3 (add both equations)

-y = -5 (multiply by -1 both sides)
y = 5

3x = 7y - 2 (substitute 5 for y)
3x = 7(5) - 2
3x = 33 (divide both sides by 3)
x = 11

Thus, the solution of the given system of the equations is x = 11 and y = 5.

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15y ago

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