3x = 7y - 2 (subtract 3x and 7y to both sides of the first equation)
9y = 4x + 1
-7y = -3x - 2 (multiply by 4 each term of both sides of the first equation)
9y = 4x + 1 (multiply by 3 each term of both sides of the second equation)
-28y = -12x - 8
27y = 12x + 3 (add both equations)
-y = -5 (multiply by -1 both sides)
y = 5
3x = 7y - 2 (substitute 5 for y)
3x = 7(5) - 2
3x = 33 (divide both sides by 3)
x = 11
Thus, the solution of the given system of the equations is x = 11 and y = 5.
3x-3x equal = 0
4x=3x+1 => (4x-3x)=1 => x=1 therefore the value of x is 1.
The equation can be simplified to show a value of Y in terms of X. 3X + 2Y +2 = 4Y + 4 3X + 2 = 2Y + 4 3X -2 = 2Y and 2Y = 3X - 2 means that Y = (3/2 X) -1
3x
3x + 2 = -10 3x = -12 x = -4
- If 3X - 1 = 11, what is the value of X^2 + X?
Given a value of x, find the value for -3x + 2
5
x=4
x=4
x = 7
It is an equation and the value of x is 6
X=-3
4
x = 4
It is an equation and the value of x is 4
If 3x - 1 = 11 what is the value of x 2 + x?