3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
3x = 2y + 3 3x -3 = 2y +3 -3 3x - 3 = 2y (3x -3)/2 = 2y / 2 y = 1/2 x (3x - 3) 3x = 2y +3 3x - 3x = -3x +2y +3 0 = -3x +2y +3 -1 x (0) = -1 x (-3x +2y +3) 0 = 3x - 2y -3
3x + 2y = 8 2y=8-3x y=4-1.5x A quadratic has x^2 This is the equation of a line with negative slope.
Your answer can be solved by rewriting the equation in point-intercept notation. * -3x + 2y = 11 * 2y = 3x + 11 * y = (3x+11)/2 That line lists all of the possible answers.
Combine like terms. 6x - 2y +7.
-3x + 2y = 9 2y = 3x + 9y = 1,5x + 4,5
You can't simplify it any further than 3x+2y+6z=24, unless you have been given values of x,y and z or other equations to find x,y and z.
3x-2y+9+9y-x = 2x+7y+9
3x + 2y = 7
-5(x + 2y) -3x + 8y + 5 = -5x -10y -3x + 8y + 5 = -8x -2y + 5
-5y2+3x+2y
(2, -1)
3x-2y-7=0
3x = 2y + 7 The standard form is: 3x - 2y - 7 = 0
3x+2y = 1 2y = -3x+1 y = -1.5x+0.5
3x+2y=6 2y=-3x+6 y=-1.5x+3