n would equal 2.5 because if 6n = 15 then you would divide 6 from both sides leaving n= 15/6 and then n=2.5 (^-^)
6 x n = 90 n = 15
-24
15+2*n = 9 2*n = -6 n = -3
t(n) = (n+1)*(n+2)/2 where n = 1 ,2, 3, ...
The pattern at each stage is the addition of a square number of increasing value to the previous term. 1 + 12 = 2 2 + 22 = 6 6 + 32 = 15 15 + 42 = 31 31 + 52 = 56 56 + 62 = 92 The formula for the nth term is, a(n) = n3/3 + n2/2 + n/6 + 1 or it can be written a(n) = 1/6(2n3 + 3n2 + n + 6) So the 7th term = 1/6(686 + 147 + 7 + 6) = 1/6 x 846 = 141 ( = 92 + 72) NOTE : The rule is the same as the sum of the squared numbers plus one. So another way of presenting the formula is, a(n) = 1/6[n(n + 1)(2n + 1)] + 1
Let N = the fractionEquation: 6 = N * 15or15N/15= 6/15N = 6/15 6 is what fraction of 15
15 - n when n equals 9 = 6
15 - n/6 = n/6 - 1 16 = 2n/6 8 = n/6 n = 48 Check it. 15 - 8 = 8 - 1 It checks.
6 x n = 90 n = 15
n is 6
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It is an equation and the value of n is 6
Let the two numbers be 'm' & 'n' Sum = m + n = -9 Product is mn = -90 Hence m = -90/n Substitute -90/n + n = -9 Multiply through by 'n' -90 + n^2 = - 9n n^2 + 9n - 90 = 0 It is now in quadratic form ; factor (n + 15)(n - 6) = 0 n = -15 & n = 6
5/8 < n/6 6*5/8 < n ie n< 15/4 or 3.75
6 + n < 21 Subtracting 6 from both sides: n < 15
let suppose total number of nodes/computers = n the formula will be = n(n-1)/2 e.g = 6(6-1)/2 =15 links.
it is C 6 H 15 N,