13
If CB is the hypotenuse, then AB measures, √ (62 - 52) = √ 11 = 3.3166 (4dp) If AB is the hypotenuse then it measures, √ (62 + 52) = √ 61 = 7.8102 (4dp)
12
It depends on where arc AC is.
AC = 2*sqrt(3) = 3.4641AB = 2*sqrt(7) = 5.2915 angle ACB = 90 degrees.
Area = 10 sq cm
90
150 degrees
Measure it with a ruler.
If the measure of minor arc AC is 96 degrees, then the measure of angle ABC, which is inscribed in the circle and subtends arc AC, can be found using the inscribed angle theorem. This theorem states that the measure of an inscribed angle is half the measure of the arc it subtends. Therefore, the measure of angle ABC is 96 degrees / 2 = 48 degrees.
30 degrees
An angle that measures between 0 and 90 degrees is an acute angle.
If CB is the hypotenuse, then AB measures, √ (62 - 52) = √ 11 = 3.3166 (4dp) If AB is the hypotenuse then it measures, √ (62 + 52) = √ 61 = 7.8102 (4dp)
149
Here is the answer to your query. Consider two ∆ABC and ∆PQR. In these two triangles ∠B = ∠Q = 90�, AB = PQ and AC = PR. We can prove the R.H.S congruence rule i.e. to prove ∆ABC ≅ ∆PQR We need the help of SSS congruence rule. We have AB = PQ, and AC = PR So, to prove ∆ABC ≅ ∆PQR in SSS congruence rule we just need to show BC = QR Now, using Pythagoras theorems in ∆ABC and ∆PQR Now, in ∆ABC and ∆PQR AB = PQ, BC = QR, AC = PR ∴ ∆ABC ≅ ∆PQR [Using SSS congruence rule] So, we have AB = PQ, AC = PR, ∠B = ∠Q = 90� and we have proved ∆ABC ≅ ∆PQR. This is proof of R.H.S. congruence rule. Hope! This will help you. Cheers!!!
12
67 degrees
An ammeter measures the amount of current flowing through an electrical circuit. It measures amperage.