Four outcomes, three combinations.
you cam make 36 different combinations.Ans 2.If you roll one dice twice, there are 36 combinations, if and only if you count 1,2 as different from 2,1.If you are rolling two dice (at once) there are only 21 different combinations !
well, 123 213 312 321 132 231 that's all
4*3*2*1 = 24 different combinations.
Only one.
4
12
256 iThink * * * * * It depends on combinations of how many. There is 1 combination of 4 letters out of 4, 4 combinations of 3 letters out of 4, 6 combinations of 2 letters out of 4, 4 combinations of 1 letter out of 4. Than makes 15 (= 24-1) in all. Well below the 256 suggested by the previous answer.
Two make combinations you would take 2x1=2 combinations only
4! = 4*3*2*1 = 24 of them.
Unjumbling letters to form words is a favorite pastime of many. The process involves looking for patterns or possible letter combinations. It can be a trial and error process. This letters can form the words true and stiff.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
Their is 25 combinations
Suppose the 5 letters are A, B, C, D and E. The letter A can either be in the combination or not: 2 options for A. With each of these options, B can either be in the combination or not: 2 options for B - making 2*2 options so far. With each of the options so far, C can either be in the combination or not: 2 options for C - making 2*2*2 options so far. and so on. So for 5 letters there are 25 = 32 combinations. However, one of these is the combination that excludes each of the 5 letters - ie the null combination. Excluding the null combination gives the final answer of 31 combinations.
262/2*102/2 = 67600/4 = 16900
There are a total of 15 letters in "season greetings." To calculate the number of words that can be formed, we first need to determine the number of unique arrangements of these letters. This can be calculated using the formula for permutations of a multiset, which is 15! / (2! * 2! * 2! * 2! * 2! * 2! * 1!). This results in 1,816,214,400 unique arrangements. However, not all of these arrangements will form valid English words, as many will be nonsensical combinations of letters.
There are 26 characters in the English alphabet, plus 10 numerals. The total amount of combinations for 2 alphanumeric chars is given by (26+10)²=1296 If you also include capital letters then the result is (26+26+10)²=3844 Only letters gives 26²=676