Assuming you are using the standard English alphabet, the number of combinations you can make are:
26 x 26 = 676 combinations.
Four outcomes, three combinations.
you cam make 36 different combinations.Ans 2.If you roll one dice twice, there are 36 combinations, if and only if you count 1,2 as different from 2,1.If you are rolling two dice (at once) there are only 21 different combinations !
well, 123 213 312 321 132 231 that's all
Only one.
4*3*2*1 = 24 different combinations.
4
12
256 iThink * * * * * It depends on combinations of how many. There is 1 combination of 4 letters out of 4, 4 combinations of 3 letters out of 4, 6 combinations of 2 letters out of 4, 4 combinations of 1 letter out of 4. Than makes 15 (= 24-1) in all. Well below the 256 suggested by the previous answer.
Two make combinations you would take 2x1=2 combinations only
Unjumbling letters to form words is a favorite pastime of many. The process involves looking for patterns or possible letter combinations. It can be a trial and error process. This letters can form the words true and stiff.
4! = 4*3*2*1 = 24 of them.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
Suppose the 5 letters are A, B, C, D and E. The letter A can either be in the combination or not: 2 options for A. With each of these options, B can either be in the combination or not: 2 options for B - making 2*2 options so far. With each of the options so far, C can either be in the combination or not: 2 options for C - making 2*2*2 options so far. and so on. So for 5 letters there are 25 = 32 combinations. However, one of these is the combination that excludes each of the 5 letters - ie the null combination. Excluding the null combination gives the final answer of 31 combinations.
262/2*102/2 = 67600/4 = 16900
Their is 25 combinations
To calculate the number of license plates with 3 letters followed by 2 digits, we consider that there are 26 letters in the English alphabet and 10 digits (0-9). For the letters, there are (26^3) combinations, and for the digits, there are (10^2) combinations. Therefore, the total number of license plates is (26^3 \times 10^2 = 17,576,000).
To find the number of unique combinations of the letters in "AABbCc", we use the formula for permutations of a multiset: [ \frac{n!}{n_1! \times n_2! \times n_3! \times \ldots} ] Here, (n) is the total number of letters (6), and (n_1, n_2, \ldots) are the frequencies of each unique letter. We have 2 A's, 1 B, 1 C, and 2 lowercase letters (b and c). Thus, the calculation is: [ \frac{6!}{2! \times 1! \times 1! \times 2!} = \frac{720}{4} = 180 ] So, there are 180 unique combinations.