Well, if John is 4 and he's twice as old as Mary, then Mary must be 2 years old. It's simple math, honey. So, Mary is just a wee little 2-year-old compared to John strutting around at the ripe old age of 4.
Mike is 12. Mary is 4. In 4 years, Mike will be 16 and Mary will be 8. So Mike will be twice as old as she is in four years.
The ages are 8 and 4
42/4 = 10.510.5*3=31.5
Krishna is 12 and three times as old as his brother, who must be 4. In 4 years time when Krishna is 16 he will be twice as old as his brother, who will then be 8.
her brother is 4 years old
Mary is 4 years old. [A+]
^^^ I have to write a Algebraic Statement
Mike is 12. Mary is 4. In 4 years, Mike will be 16 and Mary will be 8. So Mike will be twice as old as she is in four years.
John is 9 years old!!=)
12,4...16,8
Write and solve two simultaneous equations. a = Mary's age b = Mike's age Age now: b = 3a Age in 4 years: b + 4 = 2(a + 4)
Ann's 18.We can check this answer easily. Right now, Mary is 24 and Ann is 18. That means that six years ago, Mary was 18 and Ann was 12. In other words, Mary is now twice as old (24) as Ann was (12) when Mary was as old as Ann is now (18).On the other hand, this is a classic brainteaser from the 1903 New York Times -- so perhaps by now, Ann is actually well over a century old!---Note that for any given age Mary = M, Ann will be 3/4 as old (3/4 M).This is the result of the difference being 1/2 of 1/2 of Mary's age.e.g. if Mary is 60, Ann is 45So 15 years ago, Mary was 45 and Ann was 30, and Mary at 60 is twice as old as that.
The ages are 8 and 4
John is 12, and Tim is eight. Four years ago they would've been eight and four.
ken is 9 and john is 18. 4 years ago ken was 5 and John was 14. they had an age difference of 9 years.
M = 3sand(M+4) = 2 (s+4)Substitute the first equation in the second one.(3s+4) = 2 (s+4)3s + 4 = 2s + 83s = 2s + 4s = 4M = 3s = 12
42/4 = 10.510.5*3=31.5