26 degrees
Line segment BC is congruent to Line Segment YZ
Z is halfway between X and Y.
xz + x + yz + y = (x + y)(z + 1)
Using the cosine rule the three angles are as follows:- x = 75.16700977 = 75o 10' 1.24'' y = 65.6309069 = 65o 37' 51.26'' z = 39.20208333 = 39o 12' 7.5''
26 degrees
48 APEX- class of 2012 hooah us army
__ - __ AC = XZ = is the similar sign
Line segment BC is congruent to Line Segment YZ
If two triangles have the same shape but one is an enlargement of the other they are said to be similar. The two triangles must be equi-angular. To prove that ∆ABC is similar to ∆XYZ it is necessary to prove one of the following :- 1) Two angles in ∆ABC are equal to two angles in ∆XYZ, since it follows that the third angles will also be equal. 2) The three sides of ∆ABC are proportional to the corresponding sides of ∆XYZ AB/XY = AC/XZ = BC/YZ 3) Two sides in ∆ABC are proportional to two sides in ∆XYZ and the angles included between these sides in each triangle are equal. AB/XY = AC/XZ and angle A = angle X.
10 cm
Assuming that x, y and z are all prime, then they are 1, 7, x, y, z, 7x, 7y, 7z, xy, xz, yz, 7xy, 7xz, 7yz, xyz, 7xyz.
XZ
2z + 5 - xz
mid point of xy
Z is halfway between X and Y.
8.3