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What else can I help you with?
When does the product of 2 integers equal zero?
When one or both of the integers is/are zero.a*b=0 if a=0, b=0, or both a and b are equal to 0. In other words, if one or both integers are zero.
Prove that if a and b are rational numbers then a plus b is a rational number?
Because a is rational, there exist integers m and n such that a=m/n. Because b is rational, there exist integers p and q such that b=p/q. Consider a+b. a+b=(m/n)+(p/q)=(mq/nq)+(pn/mq)=(mq+pn)/(nq). (mq+pn) is an integer because the product of two integers is an integer, and the sum of two integers is an integer. nq is an integer since the product of two integers is an integer. Because a+b equals the quotient of two integers, a+b is rational.
What is the sun of four integers whose average is 15?
I assume you meant "sum". The answer is 60. 60=4 (integers) * 15 (average value of the integers). average of 4 integers = 15 --> (a + b + c + d)/4 = 15 --> (a + b + c + d) = 15 * 4 --> (a + b + c + d) = 60
Is addition of integers commutative?
Yes it is : a + b = b + a for all integers a and b. In fact , if an operation is called addition you can bet that it is commutative. It would be perverse to call an non-commutative operation addition.
Can you add two irrational numbers to get an rational number?
NoA rational number is a one that can be written as a fraction i.e a/b. where a and be are integers (whole numbers)Considera/b and c/d. Where a b c and d are integers and as such rational numbersa/b + c/d = (ad + bd)/cdad, bd and cd will all be integers and as such a/b + c/d will always be rational
Are all negative rational numbers integers?
No, they are not because fractions can be negative also. fractions aren't integers
Is sum of two integers is equal to the difference of the same two integers?
No, the sum of two integers is not equal to the difference of the same two integers, except in specific cases. For two integers ( a ) and ( b ), the sum is ( a + b ) and the difference is ( a - b ). These two expressions can only be equal if one of the integers is zero or if they are equal (i.e., ( a = b )). In general, the sum will be greater than or less than the difference, depending on the values of ( a ) and ( b ).
Which are rational numbers but not integers?
Rational fractions of the form a/b where both a and b are integers, b > 0 and, in its simplified form, the denominator is not 1.
What is the difference between 2 positive integers is 40?
The two integers are A and A+40 or, equivalently, B and B-40.
How can you use addition of integers to subtract integers?
Subtracting an integer is the same as adding the additive inverse. In symbols: a - b = a + (-b), where "-b" is the additive inverse (the opposite) of b.
What do you mean of nonintegral rational numbers?
These are rational number that are not integers. In their simplest form, they are of the form a/b where a and b are integers and b is not 0 nor 1.
When does the product of 2 integers equal zero?
When one or both of the integers is/are zero.a*b=0 if a=0, b=0, or both a and b are equal to 0. In other words, if one or both integers are zero.
Can irritational numbers be integers?
No. All integers are rational numbers with no fractional part-that is, they can be written as A/B such that B goes into A evenly.
Associative principle for addition of integers?
The associative property states that, for the sum of three or more integers the order in which the summation in carried out does not make a difference to the answer. Thus, for any three integers, A, B and C: (A + B) + C = A + (B + C) and so, without ambiguity, we can write either as A + B + C. Note that A + B need not be the same as B + A. The order of the integers DOES matter. It is the order of the summing that does not.
What can you conclude if a and b are nonzero integers such that a divisible by b and b divisible by a?
That a = ±b
Prove that if a and b are rational numbers then a plus b is a rational number?
Because a is rational, there exist integers m and n such that a=m/n. Because b is rational, there exist integers p and q such that b=p/q. Consider a+b. a+b=(m/n)+(p/q)=(mq/nq)+(pn/mq)=(mq+pn)/(nq). (mq+pn) is an integer because the product of two integers is an integer, and the sum of two integers is an integer. nq is an integer since the product of two integers is an integer. Because a+b equals the quotient of two integers, a+b is rational.
A number that can be written as a quotent of two integers?
A number that can be written in the form a/b whre a and b are integers is called a rational number.
