If a and b are integers, then a times b is an integer.
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When one or both of the integers is/are zero.a*b=0 if a=0, b=0, or both a and b are equal to 0. In other words, if one or both integers are zero.
Because a is rational, there exist integers m and n such that a=m/n. Because b is rational, there exist integers p and q such that b=p/q. Consider a+b. a+b=(m/n)+(p/q)=(mq/nq)+(pn/mq)=(mq+pn)/(nq). (mq+pn) is an integer because the product of two integers is an integer, and the sum of two integers is an integer. nq is an integer since the product of two integers is an integer. Because a+b equals the quotient of two integers, a+b is rational.
I assume you meant "sum". The answer is 60. 60=4 (integers) * 15 (average value of the integers). average of 4 integers = 15 --> (a + b + c + d)/4 = 15 --> (a + b + c + d) = 15 * 4 --> (a + b + c + d) = 60
Yes it is : a + b = b + a for all integers a and b. In fact , if an operation is called addition you can bet that it is commutative. It would be perverse to call an non-commutative operation addition.
NoA rational number is a one that can be written as a fraction i.e a/b. where a and be are integers (whole numbers)Considera/b and c/d. Where a b c and d are integers and as such rational numbersa/b + c/d = (ad + bd)/cdad, bd and cd will all be integers and as such a/b + c/d will always be rational