21, 23 ...
(19, both numbers would be odd)
Do you know what odd and even means?
If you mean, "What is the largest number of digits possible in the product of two 2-digit numbers" then 99 * 99 = 9801, or 4 digits. Anything down to 59 * 17 = 1003 will have 4 digits.
from 3 digits (10x10) to 4 digits (99X99)
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To find the fraction of 4-digit natural numbers with a product of their digits that is even, we first need to determine the total number of 4-digit natural numbers. There are 9000 such numbers (from 1000 to 9999). Next, we consider the conditions for the product of digits to be even. For a number to have an even product of digits, at least one of the digits must be even. There are 5 even digits (0, 2, 4, 6, 8) and 5 odd digits (1, 3, 5, 7, 9). Therefore, the fraction of 4-digit natural numbers with an even product of digits is 5/10 * 9/10 * 9/10 * 9/10 = 3645/9000 = 809/2000.
There are five such numbers: 11, 12, 15, 24 and 36.
two
By the definition of place values representation of numbers, there cannot be any.
If you mean, "What is the largest number of digits possible in the product of two 2-digit numbers" then 99 * 99 = 9801, or 4 digits. Anything down to 59 * 17 = 1003 will have 4 digits.
from 3 digits (10x10) to 4 digits (99X99)
Because in our system of numbers 100,000 is greater than 99,999.
You had me until "product." The product of 4 digits can't be prime.
The 2-digit number must be 20, because it is the only 2-digit number whose sum of its two even digits, 2 + 0 = 2, is greater than the product of its two even digits, 2 x 0 = 0. Moreover, 20 is a product of the two consecutive integers 4 and 5.
Zero.
There are two numbers that satisfy the criteria. 38 and 83
0 and 9 or, 0 and anything really.
They are 39 and 52.
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