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y = x2 + 8x + 15 = (x + 3)(x + 5). When y = 0, one or other of the two factors must equal zero; that is, x = -3 or -5, when y = 0.
It is y. Every third letter is r, immediately followed by y, and since 117 is divisible by 3, it is r. Therefore, 118 is y.
For Geometric Progression #1 = a = 5 #2 = ar = x #3 = ar^2 = y #4 = ar^3 = 40 We need to find 'r' To do this ,divide #4 by #1 , hence ar^3 / a = 40 / 5 Hence r^3 = 8 (Notice the 'a' cancels down to leave 'r^3' Cube root both sides Hence r = 2 When r = 2 #2 = ar = 5 X 2 = 10 = x #3 = ar%2 - 5 x 2^2 = 5 x 4 = 20 = y So the geometric progression is 5,x,y,40 = 5,10,20,40
Equation of a circle with centre (x0, y0) and radius r is (x - x0)^2 + (y - y0)^2 = r^2 → circle is: (x - -2)^2 + (y - 3)^2 = 5^2 → (x + 2)^2 + (y - 3)^2 = 5^2 → x^2 + 4x + 4 + y^2 - 6y + 9 = 25 → x^2 + 4x + y^2 - 6y - 12 = 0
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(3+y)(5+y) 3*5 + 3*y + y*5 + y*y 15 + 3y + 5y + y215 + 8y + y2y2 + 8y + 15
y = 15 - 8x/3 y - 15 = -8x/3 15 - y = 8x/3 x = 3/5(15 - y) and so x = 9 - 3y/5
if your question says 5(y+3) or 5 * (y+3) then its 5y+15
80 = 3 y + 2 y + 4 + 1 80 = 5 y + 5 80 - 5 = 5 y 75 = 5 y 15 = y So Y is 15
3(4y+5) = 25 3 . 4y + 3 . 5 = 25 12 y + 15 = 25 12 y = 25 - 15 12 y = 10 y = 12:10 = 1.2
If that's y2, the answer is (y - 5)(y + 3)
Using the symbol "^" for powers: (y^15)^(1/3) = y^(15 times 1/3) = y^5.
1/3 - 1/5 = 5/15 - 3/15 = 2/15. For any pair of reciprocals, 1/x and 1/y, 1/x - 1/y = (y - x)/xy.
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3x - y = 0 5y = 15 5y = 15 Divide by '5' on both sides Hence y = 3 Substitute for 'y' in the first equation./ 3x - 3 = 0 3x = 3 Divide both sides by ;3; x = 1 So in ( x,y) form the answer is ( 1,3).
I'm betting you meant 6x-3y=15. I'm going to factor this. 3(2x-y)=15 3(2x-y)/3=15/3 2x-y=5 Let's assume y=-1, shall we? 2x-(-1)=5 2x+1=5 2x+1-1=5-1 2x=4 2x/2=4/2 x=2 Let's plug them into the original equation, shall we? 6(2)-3(-1)=15 12-(-3)=15 12+3=15 15=15 It's true.