(-5, 2)
The x-intercept is (15 0)
5y + x = 0 subtract 5y from each side, then x = -5y
x = 0 and y = 4
x=(-5y-1)/3
(-5, 2)
2x-5y+15=0 -5y=-2x-15 y=(2/5)x+3
-3x + 5y = -15At the x-intercept, y=0:-3x = -15 . . . . . x = 5At the y-intercept, x=0:5y = -15 . . . . . y = -3
-10
The x-intercept is (15 0)
3xy - 3xy = 0
5y=25x 25x=5y -5y 25x-5y=0
They are at coordinates of: (0, -6) and (15, 0) respectively
x - 2y = 1 → x = 1 + 2y 3xy - y² = 8 Substitute the first equation into the second equation and subtract 8 from both sides: 3(1 +2y)y - y² = 0 3y +6y² - y² - 8 = 0 5y² + 3y - 8 = 0 When factored: (5y +8)(y -1) = 0 Therefore: y = -⁸/₅ or y = 1 Substituting the above values into the linear equation gives the solutions as: (3, 1) and (-¹¹/₈, -⁸/₅)
5y + x = 0 subtract 5y from each side, then x = -5y
3x - 5y = 45At the y-intercept, x = 0.-5y = 45y = -9At the x-intercept, y = 0.3x = 45x = 15
x = 0 and y = 4