Radius is half the diameter, so 25 yards.
1974/3.14=628.66 meters
50,000 square yards
So you have a rectangular field with the two ends semicircles? The rectangular area is 95 yards by 49 yards = 4655 square yards The circular part is pi x diameter squared /4 = 3.14x49x49/4 = 1884.785 sq yds Total area is 1884.785 + 4655 = 6539.785 sq yds At cost of 0.08 per sq yd that is .08 x 6539.785 = $523.18
We assume that Neptune is a sphere. It's diameter is 34,503 miles, so it's radius is 17,251.5 miles. The surface area of a sphere is 4 Pi r2. A pro football field is 120 by 53.3 yards. We need to have the same units on the top and bottom of our fraction, so convert 17,251.5 miles to yards using * ( 5280 ft/mile ) / ( 3 yards/foot ) and squaring it for area. (4*3.1415927* 17251.5 * (5280/3)2 ) / ( 120 * 53.3 ) = 104,991,372 (truncated to an integer), or just under 105 million football fields.
(a football field)0.5 A football field is not a number or a quantity and so cannot have a square root. The length of a football field can have a square root, its width can, its area can, but it cannot.(a football field)0.5 A football field is not a number or a quantity and so cannot have a square root. The length of a football field can have a square root, its width can, its area can, but it cannot.(a football field)0.5 A football field is not a number or a quantity and so cannot have a square root. The length of a football field can have a square root, its width can, its area can, but it cannot.(a football field)0.5 A football field is not a number or a quantity and so cannot have a square root. The length of a football field can have a square root, its width can, its area can, but it cannot.
Flawed Question - A field goal is not circular. It is shaped like a big 'U' on a stick.
It's easy when there are two circular plates close together compared with their diameter. In that case the E-field is the voltage divided by the distance.
1974/3.14=628.66 meters
area of object = (1/3) pi * radius^2 = (1/3) (pi) * (0.6)^2 = 0.377 Find the diameter of this object (assuming it's a circle), and that's the answer: diameter = radius * 2 radius = square root (area / pi) diameter = 2 * square root (area / pi) diameter = 2 * (0.335) = 0.67
Since the field of view is a circle, the size of the field of view is it's area. You would need to find the diameter of the field of view, using a transparent ruler or a micrometer. Divide the diameter measurement by 2 to get the radius. Then use the formula for the area of a circle, Area = πr2. For example, you measure the diameter of the field of view to be 2.14mm. Divide 2.14mm by 2 to get the radius, and you get 1.07mm. Square 1.07mm, which is 1.14mm2. Multiply x 3.14 (pi), and you get 3.58mm2. So the field of view for this example would be 3.58mm2.The field of view differs with different magnifications. The lower the magnification, the larger the field of view.
CIRCUMFERENCE=2PIE R2 2*22/7*R2=28 =ROOT 49/11 SO VOLUME=4/3 PI R2 =4/3*22/7*49/11 =18.6 bar inch3
Field diameter of lens B equals field diameter of lens A times total magnification of lens A divided by total magnification of lens B
Magnification is inversely proportional to the diameter of the field of view.
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The circumference of the center circle of a soccer field is pi times its diameter (which is 10 yards). It could also be expressed as 2 times pi times its radius (which is 5 yards). It's about 31.416 yards.
The question had errors. Edit: If the Earth's magnetic field is 5x10^-5 Tesla, then what is the radius of the circular orbit for an electron with speed 5.0x10^6 meters per second? I thought using the formula B=(uI)/2r would work, (where I = q/(r2pi/v)), and I got the answer r = 4x10^-8, which is apparently not the correct answer. Or an equation would be r = (mv)/(qB) This should probably work
The field of vision shrinks as the magnification gets higher so as the magnification increases the less of the diameter of the microscopic field you can see.