0
What else can I help you with?
if the dividend and the quotient are both odd numbers how often must the divisor be odd?
Always.
If the product of two numbers is positive then the two numbers must both be positive?
No! If one number is negative and the positive is greater than it's interval (positive version [e.g. the interval of -6 is 6]), then the product will very well be positive. In theory, of course. Sorry, tenth grader speaking... Small error here; product is the result of multiplication. The answer above is correct for a sum, but not a product. The rule for a product is even simpler than for a sum :- If the two numbers have the same signs (both positive or both negative) then the result will be positive. If the numbers have different signs the result will be negative.
Is the product of an even number of negative numbers positive?
Yes because the product of each pair of negative numbers must be positive.
What are positive and negative whole numbers and zero?
Whole numbers are numbers from 0 to infinity. They must be numbers that are not fractions or decimals, and must be positive. Integers can be any numbers that are whole, negative or positive. Zero is not a positive number. Neither is it negative. Rational numbers are an fraction. Eg: 6/10 or 6/6 They can also be whole numbers because 6/6 is also 1. Counting numbers are also numbers 1-infinity, but once again, it is all whole numbers, meaning that they are not decimals or some thing like: .1 or 1/2
Is the product of two positive mixed numbers ever less then 1?
No. A mixed number must be greater than 1, and two numbers that are greater than one that are multiplied together end up being greater that either number by itself.
if the dividend and the quotient are both odd numbers how often must the divisor be odd?
Always.
If two positive numbers sum to N what must the numbers be so that their product is maximum?
Both must be the positive square root of N.
What can you say about the quotient of a positive integer and a negative integer?
The quotient must be negative.
When a positive number equals its divisor the quotient must be?
1
Find a counterexample to show that the conjecture is false?
if the qoutient of two numbers is positive, then both numbers must be a rectangle.
What two numbers have the quotient of 9 and have a product of 36 and a difference of 0?
None. If the two numbers have a quotient of 9 then one of them must be 9 times as large as the other. In that case, their difference cannot be 0.
What is the quotient of two numbers is equal to the sum of those numbers?
If we insist on the condition that all the numbers must be integers... The only way this can happen is if the quotient and one of the other numbers are negative. For example, if the original numbers are -4 and 2, then their sum is -2, and the quotient of -4 divided by 2 is also -2. I believe that's the only integer example of a set of numbers satisfying that criterion.
If the product of two numbers is positive then the two numbers must both be positive?
No! If one number is negative and the positive is greater than it's interval (positive version [e.g. the interval of -6 is 6]), then the product will very well be positive. In theory, of course. Sorry, tenth grader speaking... Small error here; product is the result of multiplication. The answer above is correct for a sum, but not a product. The rule for a product is even simpler than for a sum :- If the two numbers have the same signs (both positive or both negative) then the result will be positive. If the numbers have different signs the result will be negative.
Is the product of an even number of negative numbers positive?
Yes because the product of each pair of negative numbers must be positive.
A neutral object must have?
equal numbers of positive and negative charges.
Is 17.5 a composite number?
No, composite numbers must be positive integers.
Is -14 rational number?
nope. rational numbers must be positive.
