Both must be the positive square root of N.
Yes because the product of each pair of negative numbers must be positive.
An absolute value must be greater or equal to zero. If the absolute value is known to be nonzero then it must be greater than zero: that is, it must be positive. The product of two (or more) positive numbers must be positive.
31
If all three numbers are positive then the product obviously has to be positive. If TWO of the three numbers are negative, then the product is also positive. But if exactly ONE of the three numbers is negative or if all THREE are negative, then the product must be negative. In general, a product of numbers is negative if an ODD NUMBER of the terms is negative.
No! If one number is negative and the positive is greater than it's interval (positive version [e.g. the interval of -6 is 6]), then the product will very well be positive. In theory, of course. Sorry, tenth grader speaking... Small error here; product is the result of multiplication. The answer above is correct for a sum, but not a product. The rule for a product is even simpler than for a sum :- If the two numbers have the same signs (both positive or both negative) then the result will be positive. If the numbers have different signs the result will be negative.
Assuming the two numbers must be positive whole numbers, the answer is 1 and 11. If they need to be non-negative, it is 0 and 12. If negative numbers are permitted (eg -1 and 13) there is no limit to the sum - ie there is no maximum.
For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.
Yes, but not always because the quotient of two negative numbers will be positive as for example -6/-2 = 3
81
One or both of the numbers must be zero.
1730
None. The sum or product of any two even numbers must be even.